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olya-2409 [2.1K]
3 years ago
6

If the same experiment is repeated in different parts of the world by different scientists,

Physics
2 answers:
laiz [17]3 years ago
6 0

What was the answer please?

Misha Larkins [42]3 years ago
3 0
The answer is D) The outcome of the experiment will be non observable
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I don’t understand this question
hichkok12 [17]

It's Z.

Without any force acting on it an object travels in a straight line.

In order to bend away from a straight line the object needs a force acting on it.

In order to move along a circle, the force on the object points toward the center of the circle. It's called the centripetal force.

Since the object's direction is changing it has acceleration.

The acceleration points toward the center of the circle.

6 0
3 years ago
Which component of the eye contains the visual receptors
juin [17]
'Retina' of the eye contains the visual receptors.
7 0
3 years ago
What is the drivers displacement at the end of the lap
NeX [460]

Answer:

The distance that the racecar traveled is indeed 500m. But at the end of the lap, it is right back where it started. So overall, it has been displaced 0m.

Explanation:

4 0
3 years ago
An applied pulling force of 100 N is used to accelerate an object to the right along a rough surface that offers 40 N of frictio
blondinia [14]

Answer:

9.8 m/s^2

Explanation:

First of all, we analyze the vertical direction.

Along this direction, the object is in equilibrium, so its acceleration is zero, and therefore  the net force on it is zero. There are only two forces acting on the object vertically: the weight, W (downward), and the normal force, N (upward), and since the net force must be zero, we can write

W=N

And since N = 60 N, the weight of the object is

W = 60 N

From this, we can also find the mass of the object, using the equation:

W=mg \rightarrow m = \frac{W}{g}=\frac{60}{9.8}=6.1 kg

where g=9.8 m/s^2 is the acceleration of gravity.

Now we analyze the forces along the horizontal direction. We have:

A pulling force of F=100 N forward

A frictional resistance of F_f = 40 N backward

So the equation of motion in this direction is

F-F_f = ma

And solving for a, we find the acceleration of the object:

a=\frac{F-F_f}{m}=\frac{100-40}{6.1}=9.8 m/s^2

in the horizontal direction, forward.

4 0
3 years ago
What is the specific heat of a 93g steel table contains 1124J of heat energy as its temperature drops 25C?
alekssr [168]

Answer:

2.335c

Explanation:

3 0
3 years ago
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