I believe it would be a musical note
Question:
A) C6H6
B) CH3CH2CH2CH2CH2COH6
C) NaCl
D) NH3
Answer:
The correct option is;
A) C₆H₆
Explanation:
Heat of fusion = 6.02 kJ/mol
Heat of vaporization =40.8 kJ/mol
Here, we analyze each of the options as follows
A) C₆H₆
Benzene has a melting point of 5.5° C and a boiling point of
80.1 ° C similar to water
Heat of fusion = 9.92 kJ/mol
Heat of vaporization =30.8kJ/mol
B) CH₃CH₂CH₂CH₂CH₂COH₆
The above compound is more likely solid
C) NaCl solid
D) NH₃ melting point = -77.73 °C boiling point = -33.34 °C
Of the above, the compounds the one that closely resembles water is C₆H₆
Answer: C
Explanation: Side post terminals need to be removed to inspect them for corrosion.
Over tightening the terminal bolt can damage side post terminals.
The battery terminals and cable ends can corrode especially when the battery or car is not used for a long period of time. Corrosion limits a battery's lifespan and so should be prevented. To inspect the areas where corrosion occur on a side-post battery, you need to remove the terminals.
Also, it is true that over tightening the terminal bolt can damage the side post terminals. The covering on the battery can become twisted, and make the seals on the terminals leak.
In fact, entropy of an isolated system never decreases (2nd law of thermodynamics), unless some external energy is provided in order to "restore" order in the system and decrease its entropy.
(note that when external energy is added to the system, it is no longer "isolated").
*This is only true if the question is referring to a certain system within the universe. If we are considering the universe itself as the system, then this option is no longer correct, because no external energy can be provided to the universe, and since the universe is an isolated system, its entropy can never decrease. If we are considering the universe itself as the system, none of the options is true.
Answer:
Amount of Energy transferred 
Explanation:
Given:
Initial volume=V
Initial pressure=P
Final volume=2V
Final pressure=3P
Now w know that the Energy transferred in constant pressure pressure is given by

Now the Energy transferred in constant volume process is given by

The total Energy transferred is given by
