All categories

3 years ago

What force is required to accelerate a 385 kg couch at 0.2 m/s^2 ?

Physics

1 answer:

Juliette [100K]3 years ago

6 0

Answer:

It takes 77 N

Explanation:

Using Newton's second law of motion, F=ma (Force equals mass times acceleration. Since the mass of the couch is 385 kg and the target acceleration is 0.2 m/s, you simply multiply mass times acceleration (ma) to get the total force, or 77 N.

You might be interested in

What is the volume of an object that has a density of 65g/cm3 and a mass of 130g.

lora16 [44]

Density ρ is mass m per unit volume v, or

ρ = m / v

Solving for v gives

v = m / ρ

So the given object has a volume of

v = (130 g) / (65 g/cm³) = 2 cm³

5 0

3 years ago

Neon is compressed from 100 kPa and 24°C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and

trasher [3.6K]

Answer:

ΔV = -0.97 m³/ kg

ΔH = 0 kJ/ kg

Explanation:

To determine the change in the specific volume we need to use the ideal gas law:

$PV = RT$

where P: pressure of the gas V: volume of the gas, R: ideal gas constant= 0.4119 kJ/kg.K = 0.4119 kPa.m³/kg.K and T: temperature of the gas.

The V₁, at a compressed pressure is:

$V_{1}= \frac {RT}{P_{1}}$

$V_{1}= \frac {0.4119 \frac{kPa\cdot m^{3}}{kg\cdot K} \cdot (24 + 273 K)}{100 kPa}$

$V_{1}= 1.22 \frac{m^{3}}{kg}$

Similarly, the V₂ is:

$V_{2}= \frac {RT}{P_{2}}$

$V_{2}= \frac {0.4119 \frac{kPa\cdot m^{3}}{kg\cdot K} \cdot (24 + 273 K)}{500 kPa}$

$V_{2}= 0.25 \frac{m^{3}}{kg}$

Now, the change in the specific volume because the compressor is:

$V_{2} - V_{1} = 0.25 - 1.22 \frac{m^{3}}{kg}$

$V_{2} - V_{1} = -0.97 \frac{m^{3}}{kg}$

Finally, to calculate the change in the specific enthalpy, we need to remember that neon is an ideal gas and that is an isothermal process:

$\Delta H = C_{p} \cdot \Delta T$

$\Delta H = 1.0299 \frac{kJ}{kg \cdot K} \cdot 0$

$\Delta H = 0 \frac{kJ}{kg}$

Have a nice day!

7 0

4 years ago

Two rooms are in contact. One is at 15°C and the other at 21°C. Choose the best statement concerning the heat flow.

amid [387]

A is the answer to your question

7 0

3 years ago

Read 2 more answers

Find the force needed to lift a 3000 N weight using a machine with a mechanical advantage of 15.

Soloha48 [4]

IF the machine is 100% efficient, then you only need to push at the input with a force of 200 Newtons. BUT ... you have to keep pushing the 200N 15 times as far as you want to lift the big weight.

8 0

3 years ago

Read 2 more answers

A hockey puck with mass 0.3 kg is shot across an ice-covered pond. Before the hockey puck was hit, the puck was at rest. After t

JulsSmile [24]

Answer:

The net friction force is 8.01 N

Explanation:

Net friction force = mass of hockey puck × acceleration

From the equations of motion

v^2 = u^2 + 2as

v = 40 m/s

u = 0 m/s (puck was initially at rest)

s = 30 m

40^2 = 0^2 + 2×a×30

60a = 1600

a = 1600/60 = 26.7 m/s^2

The acceleration of the puck is 26.7 m/s^2

Net friction force = 0.3 × 26.7 = 8.01 N

3 0

4 years ago

Read 2 more answers