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RUDIKE [14]
3 years ago
6

A spacecraft in outer space increases velocity by firing its rockets. How can hot gases escaping from its rockets change the vel

ocity of the craft when there is nothing in space for the gases to push against?
Physics
1 answer:
Elena-2011 [213]3 years ago
3 0

Answer:

Momentum is conserved.

Explanation:

-Momentum is conserved.

-By Newton's third law (For every action, there is an equal and opposite reaction.)-the change in momentum of gases in one direction must be balanced by an equal change in momentum of the spacecraft in the opposite direction.

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Points A and B lie above an infinite plane of negative charge that produces a uniform electric field of strength E=10 N/C. What
olasank [31]

There is no illustration of the problem provided but I'll attempt to provide an answer.

The relationship between the electric potential difference between two points and the average strength of the electric field between those two points is given by:

║E║ = ΔV/d

║E║ is the magnitude of the average electric field, ΔV is the potential difference between A and B, and d is the distance between A and B.

We are given the following values:

║E║= 10N/C

d = 3m

Plug these values in and solve for ΔV

10 = ΔV/3

ΔV = 30V

4 0
4 years ago
What is plasma made of and what are its properties.<br> why do we need to study plasma in physics
Elis [28]

Plasma is made up of about 90% water. It also has salts and enzymes.

Plasma has:

  • no fixed shape
  • no fixed volume
  • are less dense than liquids and solids

3 0
3 years ago
Read 2 more answers
When mass m is tied to the bottom of a long, thin wire suspended from the ceiling, the wire's second-harmonic frequency is 180 h
Katena32 [7]
The frequency of the nth-harmonic of a string is given by
f_n =  \frac{n}{2L}  \sqrt{ \frac{T}{\mu} }
where n is the number of the harmonic, L is the length of the string, T the tension and \mu the linear density. 

In our problem, since the mass m is tied to the string, the tension is equal to the weight of the object tied:
T=mg
Substituting into the first formula, we have
f_n =  \frac{n}{2L}  \sqrt{ \frac{mg}{\mu} }

In our problem we have n=2 (second harmonic). In the previous equation, the only factor which is not constant between the first and the second part of the problem is m, the mass. So, we can rewrite everything as
f_2 = K  \sqrt{m}
where we called 
K= \frac{2}{2L}  \sqrt{ \frac{g}{\mu} }

In the first part of the problem, the mass of the object is m and f_2 = 180 Hz. So we can write 
180 Hz = K  \sqrt{m}

When the mass is increased with an additional 1.2 kg, the relationship becomes
270 Hz = K \sqrt{(m+1.2 Kg)}

By writing K in terms of m in the first equation, and subsituting into the second one, we get
180 Hz  \sqrt{ \frac{m+1.2 Kg}{m} }=270 Hz
and solving this, we find
m=0.96 kg


5 0
4 years ago
Dez pours water (n 1.333) into a container made of crown glass (n 1.52). The light ray in ner made of crown glass (n = 1.52). Th
siniylev [52]

Answer:

The angle of the corresponding refracted ray is 34.84°

Explanation:

Given that,

Refractive index of water n= 1.33

Refractive index of glass n= 1.52

Incident angle = 30.0°

We need to calculate the refracted angle

Using formula of Snell's law

n_{i}\sin i=n_{r}\sin r

Put the value into the formula

\sin r=\dfrac{n_{i}\sin i}{n_{r}}

\sin r=\dfrac{1.52\times\sin30}{1.33}

\sin r=0.5714

r=sin^{-1}0.5714

r = 34.84^{\circ}

Hence, The angle of the corresponding refracted ray is 34.84°

8 0
4 years ago
What are the five blood serves in the body
nataly862011 [7]
Arm legs nose headsssssssssss
5 0
4 years ago
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