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tino4ka555 [31]
3 years ago
15

Two technicians are discussing disc brake rotor service. Technician A says that the inner races (bearing cups) should be removed

from the rotor before it is mounted on the lathe. Technician B says that a non-directional finish on the rotor surfaces can be obtained by using sandpaper. Which technician is correct?
A) Technician A only
B) Technician B only
C) Both technicians
D) Neither technician
Physics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

B) Technician B only

Explanation:

When working on the lathe, the bearing cups serve as a centering device while the rotor is on a bench lathe.

The outer and inner bearing seal are grease before mounting the rotor on the lathe for one-piece rotors.

The rotor surface is required to be made non-directional after machining so as to enable the proper seat of the new pads to the rotor . The rotor surface should be dressed with 120-grit to 150-grit aluminium oxide sand paper mounted on a sanding disc power tool.

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A 43 kg girl and a 7.1 kg sled are on the frictionless ice of a frozen lake, 12 m apart but connected by a rope of negligible ma
trapecia [35]

Answer:

(a) Girl acceleration =  0.15 m/s², (b) Sled acceleration =  0.93 m/s²

Explanation:

Given:

M1=Mass of girl = 43 Kg

M2= mass of Sled = 7.1 Kg

Force F= 6.6 N

To Find (a) a1 = girl acceleration  (b) a2 = sled acceleration

Solution:

F1 = F2 = F   (Newton's 3rd Law)

F=ma (Newton's 2nd Law)

(a) F = M1a1

⇒a1 = F/M1 = 6.6 N / 43 Kg = 0.15 m/s²

(b) a2 = F / M2 = 6.6 N / 7.1 Kg =  0.93 m/s²

6 0
3 years ago
A crude approximation is that the Earth travels in a circular orbit about the Sun at constant speed, at a distance of 150,000,00
Savatey [412]

Answer:

The answer is "Option B".

Explanation:

r=15\times 10^{7}\ km\ = 15\times 10^{10}\ m\\\\w=\frac{2\pi}{1\ year}\\\\=\frac{2\pi}{1\times 365.24 \times 24 \times 60 \times 60\ sec}\\\\a=w^2r\\\\=(\frac{2\pi}{1\times 365.24 \times 24 \times 60 \times 60\ sec})^2 \times 15 \times 10^{10}\ \frac{m}{s^2}\\\\

=5.940 \times 10^{-3} \ \frac{m}{s^2}\\\\=6 \times 10^{-3} \ \frac{m}{s^2}\\\\=0.006\ \frac{m}{s^2}\\\\

7 0
3 years ago
What phase is the Moon in when it appears completely dark?
Tanya [424]
New Moon appears completely dark
3 0
3 years ago
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Your outlets at home are rated at 120 V, i.e. the two prongs have on average a potential difference of 120V. If you transfer 2.7
hodyreva [135]

Answer:

E =230.4 MJ

Explanation:

As 1 mole of electron =  6X 10^23 particles.

charge of an electron is 1.6 X 10 ^-19 C

Finding Charge:

(6X10^23 ) (2.7)(1.6X10^-19 C)

i.e. 192 K C

now  to find the energy released from electrons

V=E/q

E=V X q

i.e E = 120 V X 192 K C

E =230.4 MJ

4 0
3 years ago
A solid metal sphere with radius 0.430 m carries a net charge of 0.270 nC . Part A Find the magnitude of the electric field at a
rodikova [14]

Answer:

8.46 N/C

Explanation:

Using Gauss law

E=\frac {kQ}{r^{2}}

Gauss's Law states that the electric flux through a surface is proportional to the net charge in the surface, and that the electric field E of a point charge Q at a distance r from the charge

Here, K is Coulomb's constant whose value is 9\times 10^{9} Nm^{2}/C^{2}

r = 0.43 + 0.106 = 0.536 m

E=\frac {9\times 10^{9}\times 0.270\times 10^{-9}}{0.536^{2}}=8.4581755402094007\approx 8.46 N/C

8 0
4 years ago
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