First step, i would try to figure out the slope. think of it as a typical y=mx+b linear equation as you check out the graph.
it's just rise over run (rise up this many, run over that many), and your options are (-2/3) or (-3/2)
start at the y-intercept, which is just above the middle of the graph. if you go down 2 and try to go over 3, you hit the line before you can count 3 units. that means this slope is incorrect.
go back to the y-intercept. down 3, over 2--there you go. your slope here is (-3/2), which immediately gets rid of half your answer choices for having the wrong slope
the next thing you have to do is decide <em>where</em> this graph should be shaded. the shaded region shows the domain; the white region shows what's outside of your domain. this inequality is shaded "below" which means that the y values are LESS than "(-3/2)x +1"
that eliminates another one of your answer choices; choice 3 is correct. the inequality is y < (-3/2)x + 1
if the graphs of inequalities are shaded below and the line is dotted, it's less than. if the graphs of inequalities are shaded above and the line is dotted, it's greater than. general rules for ya
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you know that (0,3) is a point and (1,1) is another point.
so now you have to replace them in the follow equations.
i did that and the right answer is the first equation => y=-2x+3
Answer:
Translate 10 units right, 9 units up
Step-by-step explanation:
translations simply take the image and move it up or down or side to side, reflections flip the image, dilation changes the dimensions of an image, and rotation rotates an image on its origin point.
Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
