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Yuki888 [10]
3 years ago
5

Show me step by step multiplication on how to answer : 1 2/5 x 1/4

Mathematics
1 answer:
Phantasy [73]3 years ago
4 0

Answer:

Step-by-step explanation:

What i would do is turn the first one into an improper fraction

7/5 x 1/4

it's easier to multiply this way

see if you can simplify any of the terms first

7     1

5     4

none of the numbers can be broken down further so we just multiply straight across

7 x 1 is 7

5 times 4 is 20

so the answer would be 7/20

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Angle 0 lies in the second quadrant and sin 0 = 3/5 cos= coy =
Elza [17]
Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has
 \sin B=\frac{opposite}{hypotenuse} = \frac{3}{5} and
 \cos B = \frac{adjacent}{hypotenuse} = \frac{4}{5}.

Since O lies in second quadrant \cos O\ \textless \ 0 and 
\cos O= -\cos B =- \frac{4}{5}.
Answer: \cos O=- \frac{4}{5}. 


3 0
4 years ago
Sal wants to know if he has enough money to buy 4 gallons of gas. If he has $15, and each gallon of gas costs $3.29, which is a
velikii [3]

Answer:

Remember that when you are making stimates, you are going to roiund to the nearest dollar. Since $3.29 is closer to 3 dollars than four dollars, Sam should use the 3 dollars figure to estimate if he can afford 4 gallons of gas.

$3+$3+$3+$3=$12 

The actual value is , so $3 per gallon is indeed a god estimate.

We can conclude that the correct answer is: $3 + $3 + $3 + $3 = 12, so Sal can afford the gas.

If this helped please rate and to be marked brainliest answer would be appreciated

Step-by-step explanation:

7 0
3 years ago
Let f(x) = x + 8 and g(x) = x2 − 6x − 7. find f(g(2)). −7 −3 10 33 open study
Ray Of Light [21]
F(g(2))

g(x) = x^2 - 6x - 7
g(2) = 2^2 - 6(2) - 7
g(2) = 4 - 12 - 7
g(2) = -15

f(x) = x + 8
f(g(2) = f(-15) = -15 + 8 = -7 <==

ur answer is -7
6 0
3 years ago
Solve for d.<br><br> Help is appreciated thank u!!
crimeas [40]

Answer:

d = 16.88

Step-by-step explanation:

Start by simplifying both sides of the equation then isolate the variable

5 0
3 years ago
Please solve the problem ​
jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==>   <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==>   <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}

Similarly, you would find

Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}

You can solve the second system in the same fashion. You would end up with

P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}

3 0
3 years ago
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