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netineya [11]
3 years ago
12

25 – 4.337 + (1 - 100)​

Mathematics
1 answer:
Sidana [21]3 years ago
6 0

Answer:

25 – 4.33 = 20.67

7 + (1 - 100)​ = -92

Step-by-step explanation:

First one) Simply use your knowledge of integers and decimals to solve this. You can even start by drawing a number line and practising with that before beginning to do harder problems.

Second one) Just like the first one but use PEDMAS, BEDMAS or BODMAS and make sure to solve the brackets first.

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Let X represent the number of hours you travelled
Let B represent number of hours Brian travelled 

Equation 1 is X + B = 20 (since combination of number of hours you and Brian travelled equal to 20 hours)
Equation 2 is M = 5B (since you travelled five times more than the amount in which Brian travelled)

Plug Equation 2 into Equation 1 (replacing M with its value)
5B + B = 20

Rearrange equation to make B its subject (find B)
6B = 20
6B/6 = 20/6
B = 3(1/3)
Brian travelled a total of 3(1/3) (three and a third) hours. 
(1/3) of an hour = 60/3  or 60*(1/3) = 20mins
Brian travelled a total of 3hrs & 20mins. 

Plug B value back into Equation 1 
M + B = 20
M + 3(1/3) = 20

Rearrange equation to make M its subject (find M)
M = 20 - 3(1/3) = 16(2/3) 
You travelled a total of 16(2/3) (sixteen and two-thirds) hours.
(2/3) of an hour = 60/3*2 or 60*(2/3) = 40mins
You travelled a total of 16hrs & 40mins. 



8 0
4 years ago
You use a 40% off coupon followed by a 30% off coupon. is that
Natalija [7]

Answer:

Yes since 40+30=70 so it would be the same

Step-by-step explanation:

6 0
3 years ago
Prove each of these identities.
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<h3><u>Answer</u><u>:</u></h3>

<u>➲</u><u> </u><u>(</u><u> </u><u>1</u><u> </u><u>+</u><u> </u><u>sec </u><u>x </u><u>)</u><u>(</u><u> </u><u>cosec </u><u>x </u><u>-</u><u> </u><u>cot </u><u>x </u><u>)</u><u> </u><u>=</u><u> </u><u>tan </u><u>x</u>

  • <em>Solving</em><em> </em><em>for </em><em>L.H.S</em>

\implies\quad \sf{(1+sec\:x)(cosec\:x-cot\:x) }

\implies\quad \sf{ \left(1+\dfrac{1}{cos\:x}\right)\left(\dfrac{1}{sin\:x}-\dfrac{cos\:x}{sin\:x}\right)}

\implies\quad \sf{ \left(\dfrac{1+cos\:x}{cos\:x}\right)\left(\dfrac{1-cos\:x}{sin\:x}\right)}

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\implies\quad \sf{ \left( \dfrac{sin^2 x}{cos\:x.sin\:x}\right)}

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\implies\quad \sf{\left( \dfrac{sin\:x}{cos\:x}\right) }

\implies\quad\underline{\underline{\pmb{ \sf{tan\:x}}} }

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\implies\quad \sf{\dfrac{sin^2x}{cos\:x} }

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7 0
3 years ago
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Heyyyy


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6 0
3 years ago
The table shows the maze-completion times, in seconds, of two sets of mice in an experiment.Which statement is true about the va
Yanka [14]
The value of Q_{1} , Q_{2} ,, and Q_{3} of each data is shown in the diagram below

Group A

Mean = \frac{41+44+45+48+49+50+52+54+55+58}{10} =49.6
Median = 49.5
Range = 58-41=17
Interquartile Range = Q_{3}- Q_{1} =54.5-44.5=10

Group B
Mean = \frac{40+41+43+45+48+52+55+57+60+62}{10}=50.3
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Correct statement: the time in Group B has a greater interquartile range

5 0
4 years ago
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