Answer:
The true statement is <u>Line h has points on planes R, P, and T</u>
Step-by-step explanation:
The rest of the question is the attached figure
According to the graph, we will check which option is true.
a. Line h intersects line f at two points, A and B (<u>Wrong</u>)
<u>Because</u>: h intersects line f at B only.
b. Line h is the intersection of planes R and T (<u>Wrong</u>)
<u>Because</u>: g is the intersection of planes R and T
c. Line h intersects plane P at point C (<u>Wrong</u>)
<u>Because</u>: h intersects plane P at point B
d. Line h has points on planes R, P, and T (<u>True</u>)
<u>Because </u>h has the point B on the plane P, h has the point A on the plane T
and the points of h on the plane R
Marla Paid 72$ or 71.99$ because 20% is 18$ so you subtract 90 by 18.
Answer:
the answer is d
Step-by-step explanation:
i just know its fine.
Answer:
-3x^6 -x^4 +2x^3 -8x +8
Step-by-step explanation:
Use the distributive property 4 times.
(-3x^3 + 2x - 4)×(x^3 + x - 2)
= -3x^3(x^3 +x -2) +2x(x^3 +x -2) -4(x^3 +x -2) . . . . once
= -3x^6 -3x^4 +6x^3 +2x^4 +2x^2 -4x -4x^3 -4x +8 . . . . 3 more times
= -3x^6 +x^4(-3+2) +x^3(6 -4) +2x^2 +x(-4 -4) +8 . . . . group like terms
= -3x^6 -x^4 +2x^3 -8x +8