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Sholpan [36]
3 years ago
8

Can someone please answer this ? * will mark as brainiest *

Mathematics
2 answers:
ipn [44]3 years ago
5 0

I believe PQ would be 12 cm.

Lena [83]3 years ago
3 0

Answer:

pq= 12 cm

Step-by-step explanation:

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it cost ruby $4 dollars to send 48 messages.what was her cost of texting in texts per dollar?express your answer in simplest for
andrew-mc [135]

Answer:

$0.83

Step-by-step explanation:

$4 = 48x (x = number of text messages)

$4 ÷ 48 = x (divide by 48 on both sides)

0.83 = x


7 0
2 years ago
Read 2 more answers
Find the center and radius of the circle with the equation : (x+5)^2 + (y-2)^2 =25
murzikaleks [220]

Answer:

Center (-5, 2) and radius 5

Step-by-step explanation:

The equation for a circle is (x-h)^{2} +(y-k)^{2} =r^{2}

Where (h, k) is the center and r is the radius.

6 0
3 years ago
Find the critical point of the given function and then determine whether it is a local maximum, local minimum, or saddle point.
34kurt

Answer:

critical point of the given function f(x,y) = x²+y²+2xy is from line y = -x is the critical point of the function f(x0,y0) = 0

and it local minimum.

Step-by-step explanation:

Let the given function be;

f(x,y) = x²+y²+2xy

From above function, we can locate relative minima, maxima and the saddle point

f(x,y) = x²+y²+2xy = (x+y)²

df/dx = 2x+2y = 0 ---- (1)

df/dy =2y+2x = 0 ---- (2)

From eqn 1 and 2 above,

The arbitrary point (x0,y0) from line y = -x is the critical point of the function f(x0,y0) = 0

Then, from f(x,y) >= 0 for arbitrary (x,y) € R^n, the arbitrary point from the line x = -y is local minima of the function f.

8 0
3 years ago
Of 300 students in the cafeteria, 180 had lunch. Write the simplified ratio of the students in the cafeteria to the students tha
yan [13]

Answer:

300 : 180 = 5 : 3

3 0
3 years ago
Read 2 more answers
Abby filled her goodie bags with 4 cookies and 3 candy bars and spent a total of $10.25 per bag. Marissa filled her goodie bags
Paladinen [302]
Let's start by writing a system of linear equations:
c -> cookies 
cb -> candy bars
(You can use any abbreviations to your preference)

Abby:
4 cookies 
3 candy bars
$10.25 per bag
The equation would be:
4c+ 3cb = $10.25

Marissa:
2 cookies
7 candy bars
$14.75 per bag
The equation would be:
2c + 7cb = $14.75

So our linear equation system would be:
<span>4c+ 3cb = $10.25
</span><span>2c + 7cb = $14.75

I would try to get rid of one variable so I can solve for the other variable. In this case, it is easier to get rid of c since I can multiply the second equations by 2. Then it would subtract the two equations.

(2c + 7cb = $14.75) 2 = 4c + 14 cb = $29.50

      4c + 3cb = $10.25
   -  4c+14 cb = $29.50                    (4c would get canceled.)
---------------------------------
             -11 cb = - $19.25                (Divide by -11 to solve for cb)
</span>             ---------   -------------
              -11           -11
            
             cb = $1.75

Now we know cb (candy bar) cost, we would substitute this value into cb into one of the equations. It doesn't matter which equation you put it in. I will substitute it in the first equations. 

  4c + 3 (1.75) = $10.25
  4c + 5.25 = $10.25                       (Multiply 3 by 1.75)
       -5.25       -5.25                         (Subtract 5.25 on both sides)
             4c = 5                                 (Divide by 4 on both sides to get c)
             ----   ---
              4      4
         
         c= 1.25

Check the work:
4(1.25) + 3(1.75) 
  = $10.25

2(1.25) + 7(1.75)
   = $14.75

Total cost:
cookies = $1.25
candy bars = $ 1.75

Hope this helps! :)

6 0
3 years ago
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