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love history [14]
3 years ago
7

Are the graphs of 6 y = -2x + 4 and y = 6x - 4 parallel perpendicular or neither

Mathematics
1 answer:
timurjin [86]3 years ago
4 0
1st slope is -1/3. 2nd slope is 6

slope is same in parallel lines so not parallel

slopes are negative reciprocals in perpendicular lines so they aren't perpendicular

they are called oblique
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9. Consider the diagram below. First, solve for x, then y.
aniked [119]

Answer:

x = 59

y = 32

Step-by-step explanation:

x + 78 + 43 = 180

x = 59

y + 59 + 89 = 180

y = 32

6 0
3 years ago
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Please help ♡♡♡♡♡♡♡♡♡​
zhannawk [14.2K]

Answer:

71°

Step-by-step explanation:

BDH is a triangle (as seen on figure)

<BDH + <DBH = <DHE ( Sum of two interior angles of a triangle is equal to the opposite exterior angle)

40° + 31° = X

X = 71°

7 0
3 years ago
What is the coeffieent of (x^4)(y^4) in the expansion of (x+y)^8
kap26 [50]
ANSWER

The coefficient is 70.

EXPLANATION

The given binomial expression is

(x+y)^8

The specific term of a binomial expansion can be determined using the formula,

T_{r+1}= nC_ra^{n-r}b^r
where

n=8,r=4,a=x,b=y

We substitute these values into the formula to get,

T_{4+1}= 8C_4x^{8-4}y^4

We simplify to get,

T_{5}= 70x^{4}y^4

Hence the coefficient is 70.
4 0
3 years ago
Which of the following are valid names for the triangle below? Check all that
Tanya [424]

Answer:

<u>A</u>

<u>B</u>

<u>E</u>

Explanation:

The first, third and fifth options are valid as it mentions the three edges; no matter what the order is as long as the three points are mentioned its considered as the valid name

5 0
3 years ago
Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 51% chan
Charra [1.4K]

Answer:

a) 0.3270 = 32.70% probability that Christine fails the course

b) 0.3917 = 39.17% probability that she had found someone to help

Step-by-step explanation:

We have these following probabilities:

61% probability that Christine find a coach.

100 - 61 = 39% probability that Christine does not find a coach.

With a coach, a 21% probability of failing.

Without a coach, a 51% probability of failing.

a. What is the probability that Christine fails the course?

21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So

P = 0.21*0.61 + 0.51*0.39 = 0.327.

0.327 = 32.7% probability that Christine fails the course

b. Christine ends up failing the course. What is the probability that she had found someone to help?

This can be formulated by the Bayes formula:

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.

In this question.

P(B|A) is the probability of finding a tutor given that she failed.

P(B) is the probability of finding a tutor. So P(B) = 0.61.

P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21

P(A) is the probability of failing. So P(A) = 0.327.

So

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.61*0.21}{0.327} = 0.3917

0.3917 = 39.17% probability that she had found someone to help

4 0
3 years ago
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