Answer:
a. mass of glucose required = 4.50 g
b. mass of glucose required = 0.05 g
c. mass of glucose required = 25g
Explanation:
1a. molar mass of glucose = 180.156 g/mol
volume of solution = 250 mL or 250 mL * 1 L/1000 mL = 0.25 L
concentration of solution = 100 mM or 100mM * 1 M/1000 mM = 0.10 M
amount in moles = mass/ molar mass = concentration * volume
mass in grams = concentration * volume * molar mass
mass = 0.10 * 0.25 * 180.156
mass of glucose required = 4.50 g
b. mass concentration of 0.05 % solution = 0.05 g/100 ml = 0.5 g/L
volume of solution = 100 mL = 0.1 L
mass in grams = mass concentration * volume
mass in grams = 0.5 g/L * 0.1 L
mass of glucose required = 0.05 g
c. mass concentration of solution = 50 mg/ mL = 0.05 g/ 0.001 L = 50 g/L
volume of solution = 500 mL = 0.5 L
mass of solute required = concentration * volume
mass required = 50 g/L * 0.5 L
mass of glucose required = 25g
