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Stels [109]
3 years ago
13

Which of the following best explains why most chemical reactions proceed more quickly when the concentrations of reactants are i

ncreased? (12 points) A.The increased concentration increases the number of collisions between molecules.
B.The products of chemical reactions are more stable at higher concentrations. C.At higher concentrations, reactant molecules move more quickly.
D.At higher concentrations, product molecules are able to catalyze the reaction.
Chemistry
1 answer:
pogonyaev3 years ago
7 0
Among many factors, the concentration of reactant is also responsible for effecting the rate of reaction. And it is found that the rate of reaction is directly proportional to the rate of reaction.

Explanation:
                     
Higher concentration means greater number of reactants in the system. Greater the number greater will be the probability of reactants to colloid. And according to collision theory reactants must colloid with optimum kinetic energy and orientation. So, in higher concentrated system the rate of collisions increases with increasing the rate of reaction.

Result:
           Option 
<span>A is correct answer. (The increased concentration increases the number of collisions between molecules.)</span>
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A sample of 87.6 g of carbon is reacted with 136 g of
Vadim26 [7]

Answer:

A. fluorine, 1.79 moles

Explanation:

Given parameters:

Mass of carbon  = 87.7g

Mass of fluorine gas  = 136g

Unknown:

The limiting reactant and the maximum amount of moles of carbon tetrafluoride that can be produced  = ?

Solution:

   Equation of the reaction:

             C    +   2F₂ →   CF₄  

let us find the number of the moles the given species;

  Number of moles = \frac{mass}{molar mass}  

  C;   molar mass = 12;

            Number of moles  = \frac{87.7}{12}   = 7.31moles

 F;  molar mass  = 2(19)  = 38g/mol

             Number of moles  = \frac{136}{38}   = 3.58moles

 So;

   From the give reaction:

          1 mole of C requires 2 moles of F₂

         7.31 moles of C will then require 2 x 7.31 moles of F₂ = 14.62moles

But we have 3.58 moles of the F₂;

  Therefore, the reactant in short supply is F₂ and it is the limiting reactant;

 So;

       2 moles of F₂ will produce  mole of CF₄  

       3.58 moles of F₂ will then produce \frac{3.58}{2}  = 1.79moles of CF₄

6 0
2 years ago
The bonds of the product store 27 KJ more energy than the bonds of the reactants how is energy conserved during this reaction
Blababa [14]

If the bonds of the product store 27 KJ more energy than the bonds of the reactants, It means the surroundings absorb 27 kj of energy from the reaction system Hence, Option (D) is the correct answer

<h3>What is the Exothermic reaction ?</h3>

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise.

The bonds of the product store 27 KJ more energy than the bonds of the reactants, It means that energy has been absorbed by the surrounding as the product formed is more stable due to more stronger bond

This can be inferred from more stored energy with in the bonds and Thus, It is a exothermic reaction.Hence, Option (D) is the correct answer

Learn more about exothermic reaction here ;

brainly.com/question/9799465

#SPJ1

6 0
1 year ago
What is the electron configuration for 1s2 2s2 2p6 3s2 3p6​
Sliva [168]
This is going to lead you to the element Argon. Is this what you are asking?
7 0
2 years ago
given that the speed of light is 2.998 x 108 m/s, what is the frequency of a wave that has a wavelength of 3.55 x 10-8 meters
Vesna [10]
Frequency, f = v / λ

f = 2.998 * 10⁸ / 3.55*10⁻⁸

f = 8.445 * 10¹⁵ Hz.
8 0
3 years ago
A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain
sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

-w=\frac{dm}{dt}

w is the mass flow

m is the mass of salt

-v*C=\frac{dm}{dt}

v is the volume flow

C is the concentration

C=\frac{m}{V+(6-3)*L/min*t}

-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}

-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}

-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)

-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)

m=90kg*[2000L/(2000L+3*L/min*t)]

a) Initially: t=0

m=90kg*[2000L/(2000L+3*L/min*0)]=90kg

b) t=210 min (3.5 hr)

m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg

c) If time trends to infinity the  division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0
3 years ago
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