53.5 g MgCl2 /95.21 g/mol = 0.5619 Moles MgCl2. Since the ratio is 3MgCl : 2Na3PO4 you multiply 0.5619 x 2/3 (since you're solving for NaPO, the 2 goes on top) which shows we have .3746 Moles of NaPO. Multiply times it's molar mass so 0.3746x 163.94g/mol= 61.4136 grams NaPO. I believe.
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I know its not the answer but i had to put something bc im jus setting this up im rlly sorry for the inconvenience but i looked it up n got a quizlet n the answer on there was 1.81x10^-4 if it helps
Answer:
The molarity of the sulfuric acid is 0.018 M
Explanation:
The molarity of a solution is the number of moles of the solute (sulfuric acid in this case) in a 1-liter solution.
Every 100 g of the solution, we have 95 g sulfuric acid because its concentration is 95% w/w.
With the density, we can calculate how many liters are 100 g of solution:
density = mass / volume
1.85 g / ml = 100 g / volume
volume = 100 g / 1.85 g/ml
volume = 54.1 ml or 0.0541 l
Now, we know that we have 95 g sulfuric acid in 0.0541 l solution. In 1 l, we have then:
1 l * 95g / 0.0541 l = 1.756 g sulfuric acid.
But we want to know how many moles sulfuric acid we have per liter. Then, using the molar mass, we can calculate how many moles there are in 1.756 g sulfuric acid:
1.756 g * 1 mol / 98.08 g = 0.018 mol
The molarity is 0.018 M
Answer:
When carbon dioxide reacts with water carbonic acid is formed, from which hydrogen ions dissociate increasing the acidity of the systemCarbon dioxide emissions to the atmosphere can therefore increase the acidity of land, sea and air
Explanation:
