Answer:
For 1 antacid tablet (in ballon1) we get .0173 moles of CO2
for 2 tablets (in balloon 2) we get: 2*0,0173= 0.0346 moles of CO2
For 3 tablets (in balloon 3) we get 3* 0.0173 = 0.0519 moles of CO2
Explanation:
The complete question:
Calculate the theoretical value for the number of moles of CO2 that should have been produced in each balloon assuming that 1.45 g of NaHCO3 is present in an antacid tablet. Use stoichiometry (a mole ratio conversion must be present) to find your answers (there should be three: one answer for each balloon).
Balloon 1 had 1 antacid tab
Baloon 2 had 2
Balloon 3 had 3
Step 1: Data given
1.45 g of NaHCO3 is present in an antacid tablet
Molar mass of NaHCO3 = 84.00 g/mol
Step 2: The balanced equation
NaHCO3 + H2O → NaOH + H2O + CO2
Step 3: Calculate moles of NaHCO3
Moles NaHCO3 = mass NaHCO3 / molar mass NaHCO3
1.45g / 84.0 g/mol = .0173 moles
Step 4: Calculate moles CO2
For 1 mol NaHCO3 we need 1 mol H2O to produce 1 mol NaOH 1 mol H2O and 1 mol CO2
For 0.0173 moles NaHCO3 we'll get 0.0173 moles CO2
so for 1 antacid tablet we get .0173 moles of CO2
for 2 tablets we get: 2*0,0173 = 0.0346 moles of CO2
For 3 tablets we get 3* 0.0173 = 0.0519 moles of CO2
