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Yuki888 [10]
3 years ago
10

Let x and y be real numbers satisfying 2/x=y/3=x/y Determine the value of x^3

Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

<h2>64/27</h2>

Step-by-step explanation:

If  x and y be real numbers satisfying 2/x=y/3=x/y, then any two of the equation are equated as shown;

2/x = y/3 ... 1 and;

y/3 = x/y... 2

From equation 1, 2y = 3x ... 3

and from equation 2; y² = 3x ... 4

Equating the left hand side of equation 3 and 4 since their right hand sides are equal, we will have;

2y = y²

2 = y

y = 2

Substituting y = 2 into equation 3 to get the value of x;

2y = 3x

2(2) = 3x

4 = 3x

x = 4/3

The value of x³ will be expressed as (4/3)³ = 4*4*4/3*3*3 = 64/27

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Answer:

2 - 8i

Step-by-step explanation:

The additive inverse of something is basically the opposite of it. Another way to say this is that when you add the additive inverse to -2 + 8i, it will equal 0.

<u>An example:</u>

The additive inverse of 7 is -7 because not only is it the opposite, but also when you add 7 and -7, it equals 0.

<u>To solve</u>

So all you need to do is find the opposite of -2 + 8i. You can write it as:

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3 0
3 years ago
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