it does not freeze in the fridge, merely turns to a solid state. how long would depend on how warm it was before you put it in the fridge.
Answer:
T2 = 94.6 C
Explanation:
Use Clausius-Clayperyon equation.
ln P1/P2 = ∆Hvap/R (1/T2 - 1/T1) where R = 8.314 J/mol-K and T is in degrees K
P1 = 760 mmHg
P2 = 630 mmHg
T1 = 373 K
T2 = ?
∆Hvap = 40.7 kJ/mole
R = 0.008314 kJ/mole-K (NOTE: change R to units of kJ)
Plug in and solve for T2
ln 760 mmHg/630 mmHg = 40.7 kJ/mole (1/T2 - 1/373K)
T2 = 367.74 K = 94.6 C
Answer:
No
Explanation:
No, but the total mass of reactants must equal the total mass of products to be a balanced equation.
Example: Consider the following reaction ...
3H₂ + N₂ => 2NH₃ and 'amu' is atomic mass units (formula weights from periodic table)
In terms of molecules, there are 4 molecules on the left (3 molecular hydrogens (H₂) and 1 molecular nitrogen (N₂) and 2 molecules of ammonia on the right side of equation arrow. ∑reactant molecules ≠ ∑product molecules.
In terms of mass of reactants & mass of products, the 3H₂ + N₂ => 6amu + 28amu = 34amu & mass of products (2NH₃) => 2(14amu) + 6(1amu) = 34amu for sum of product masses.
∑mass reactants = ∑mass products <=> 34amu = 34amu.
The expression '∑mass reactants = ∑mass products' as applied to chemical equations is generally known as 'The Law of Mass Balance'.
Answer: 14.0 moles of carbon.
Explanation: Using the Avogadro's number,
6.02 x 10^23 atoms -----> 1 mole of carbon .
8.43 x 10^24 atoms ----> 8.43 x 10^24/ 6.02 x 10^23 = 14.0moles of carbon.
Answer:
Percentage error = 
x 100%
Explanation:
In order to calculate the percentage error in the student's calculation, the following formula will be used:
Percentage error = 
x 100%
experimental molar mass = 64 g/mol
theoretical molar mass = 58 g/mol
Hence, the expression becomes:
Percentage error = x 100%
