Answer:
we only see parts of the lit side as the moon goes around the earth
Explanation:
Unlike the sun, the moon orbits the Earth. This is the reason why we see the <em>different phases of the moon.</em> The reflection of the moon is being illuminated back to us with the help of the sun. So, as the moon circles the Earth, we only see parts of the lit side. Such changes helps us see the moon in different phases such as<em> </em>the <em>Third Quarter, Crescent, New Moon, Full Moon, etc.</em>
For example, during "Full Moon," <em>the moon's entire face is lit up by the sun</em>. Thus, we see the entire moon's lit portion.
Thus, this explains the answer.
<h3><em><u>solution</u></em><em><u>:</u></em></h3>
<em><u>The initial entropy is obtained from the initial pressure and temperature with data from A-6 using interpolation:</u></em>
<em><u>s</u></em><em><u>=</u></em><em><u> </u></em><em><u>8</u></em><em><u>.</u></em><em><u>26</u></em><em><u>5</u></em><em><u>2</u></em><em><u> </u></em><em><u>kJ</u></em><em><u>/</u></em><em><u>kgK</u></em>
<em><u>The final temperature is determined from the entropy and the final pressure with data from A-6 using interpolation:</u></em>
<em><u>T₂ = T₁+</u></em><em><u> </u></em><em><u>T₂ - </u></em><em><u>T₁</u></em><em><u>/</u></em><em><u> </u></em><em><u>8</u></em><em><u>₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8</u></em><em><u>₁</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>s</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>s</u></em><em><u>₁</u></em><em><u>)</u></em>
<em><u>= </u></em><em><u>(</u></em><em><u>400 +</u></em><em><u> </u></em><em><u>500 - 400</u></em><em><u>/</u></em><em><u>8.3271</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8.0347</u></em><em><u> </u></em><em><u>(8.2652 - 8</u></em><em><u>)</u></em><em><u>)</u></em>
<em><u>= 478.83°C</u></em>
<em><u>The final enthalpy is determined in the same way:</u></em>
<em><u>h₂= h₁</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>h₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>h₁</u></em><em><u>/</u></em><em><u>s</u></em><em><u>₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>s</u></em><em><u>₁</u></em><em><u> </u></em><em><u>( s - s₁)</u></em>
<em><u>= (</u></em><em><u> </u></em><em><u>3275.5</u></em><em><u>+</u></em><em><u> </u></em><em><u>3486.6 </u></em><em><u>-</u></em><em><u> </u></em><em><u>3275.5</u></em><em><u>/</u></em><em><u> </u></em><em><u>8.3271</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8.0347</u></em><em><u>)</u></em><em><u> </u></em><em><u>(8.265</u></em><em><u>)</u></em>
<em><u>=</u></em><em><u> </u></em><em><u>3441.91 </u></em><em><u>kJ</u></em><em><u>/</u></em><em><u>kg</u></em>
Answer: If two positive charges interact, their forces are directed against each other. The two charges repel each other.
Explanation: The same occurs with two negative charges, because their respective forces also act in opposite directions.) The electric field and resulting forces produced by two electrical charges of the same polarity.
Good luck luv.
Answer:
Ok to solve this you will need to use the Ideal Gas Law Formula which is as follows:
PV = nRT
P= pressure
V= volume
n= # of moles
R= Universal Gas Constant (0.0821 L x atm/mol x K)
T= Kelvin temperature
1.Simplify the Ideal Gas Law formula to what you need to solve for:
P = (nRT)/ V
2. List all you components as follows (this makes the process easier):
P = ?
V = 45.4 L
n = 0.625 mol
R = 0.0821 L x atm/ mol x K
T = 249 K
To find the Kelvin temperature K = C + 273
3. Plug in all your components in your set up formula:
P = [(0.625 mol)(0.0821 L x atm/ mol x K)(249 K)] / (45.4 L)
4. Cross out all similar units so the only thing left is atm because you are trying to find pressure.
P = [(0.625)(0.0821atm)(249)] / (45.4)
5. Multiply through and simplify
P = 0.28 atm
B. is the correct answer.
Glad I could help!! If you have any other questions just message me. Hopefully this was helpful.
Explanation:
0.25 moles of H3PO4 is needed to
neutralize 1 liter of a 0.75M solution of NaOH. I am hoping that this answer
has satisfied your query and it will be able to help you in your endeavor, and
if you would like, feel free to ask another question.