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weqwewe [10]
2 years ago
11

When interviewed, Mr. Harrison was discussing barometric pressure and the low-pressure system moving in that may cause a change

in precipitation and wind gusts. Mr. Harrison is most likely _____.
Chemistry
2 answers:
Zarrin [17]2 years ago
6 0

A meteorologist?? I could be totally wrong though! :)


Verizon [17]2 years ago
6 0

Answer:

Meteorologist

Explanation:

<u>A meteorologist by profession is a person that deals with the study of the atmosphere, climate and weather patterns and the interaction between them occurring at different places on earth</u>. It provides the idea and necessary conditions about how these climatic variation occurs at various places and what are its controlling factors.

It gives a picture of the atmospheric structure and its variations at different altitudes with respect to temperature and pressure. It also provides the basic conditions for the formation of tornadoes, hurricanes, and cyclones.

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Conversation 13kg into gram<br>4 poi ts<br>​
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Answer:

13000

Explanation:

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3 years ago
What is the freezing point of a solution prepared from 45.0 g ethylene glycol (C2H6O2) and 85.0 g H2O? Kf of water is 1.86°C/m.
Andrews [41]

Answer:

T_{sol}=-15.9\°C

Explanation:

Hello,

In this case, we can analyze the colligative property of solutions - freezing point depression - for the formed solution when ethylene glycol mixes with water. Thus, since water freezes at 0 °C, we can compute the freezing point of the solution as shown below:

T_{sol}=T_{water}-i*m*Kf

Whereas the van't Hoff factor for this solute is 1 as it is nonionizing and the molality is:

m=\frac{mol_{solute}}{kg\ of\ water}=\frac{45.0g*\frac{1mol}{62g} }{85.0g*\frac{1kg}{1000g} } =8.54m

Thus, we obtain:

T_{sol}=0\°C+(-8.54m*1.86\frac{\°C}{m} )\\\\T_{sol}=-15.9\°C

Best regards.

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