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3 years ago

Is pre ap chemistry hard in high school?

2 answers:

8 0

If you don't practice enough it's obviously going to be hard but if you practice enough it's going to be a piece of cake so don't think if it's going to be hard or not just think it's going to be worth the try at the very end

choli [55]3 years ago

4 0

Depends on how good u are at studying or taking notes if your good at that you should be fine

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Calculate the standard cell emf for the reaction: ClO3−(aq)+3Cu(s)+6H+(aq)→Cl−(aq)+3Cu2+(aq)+3H2O(l) Pt is used as an inert elec

Rama09 [41]

Answer: The standard EMF of the cell is 1.11 V

Explanation:

For the given chemical equation:

$ClO_3^-(aq)+3Cu(s)+6H^+(aq.)\rightarrow Cl^-(aq.)+3Cu^{2+}(aq.)+3H_2O(l)$

The half reaction follows:

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}+2e^-;E^o_{Cu^{2+}/Cu}=0.34V$ ( × 3)

Reduction half reaction: $ClO_3^-(aq.)+6H^+(aq.)+6e^-\rightarrow Cl^-(aq.)+3H_2O(l);E^o=1.45V$

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Calculating the $E^o_{cell}$ using above equation, we get:

$E^o_{cell}=1.45-0.34=1.11V$

Hence, the standard EMF of the cell is 1.11 V

6 0

3 years ago

At STP, which gas sample has a volume of 11.2 liters?

Natasha2012 [34]

Answer:

0.500 moles of CO2 has a volume of 11.2 L at STP (option B)

Explanation:

Step 1: Data given

Volume of a gas at STP = 11.2 L

STP: Pressure = 1 atm and temperature = 273 K

Step 2: Calculate volume

p*V= n*R*T

V = (n*R*T)/p

⇒with V = the volume of the gas = TO BE DETERMINED

⇒with n = the number of moles of the gas

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 273 K

⇒with p = the pressure of the gas = 1 atm

A ) 0.250 mole of NH3

V = (0.250 * 0.08206 * 273) / 1

V = 5.6 L

B ) 0.500 mole of CO2

V = (0.500 * 0.08206 * 273) / 1

V = 11.2 L

C ) 0.750 mole of NH3

V = (0.750 * 0.08206 * 273) / 1

V = 16.8 L

D) 1.00 mole of CO2

V = (1.00 * 0.08206* 273) / 1

V = 22.4 L

0.500 moles of CO2 has a volume of 11.2 L at STP (option B)

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4 years ago

In general, the ________ of a simple machine is the ratio of the distance over which the force is applied to the distance over w

madreJ [45]

The answer that best fits the blank provided above is MECHANICAL.

7 0

3 years ago

¿Cuántos litros de oxígeno en condiciones normales se producen a partir de 0,45 mol de O2?

Lerok [7]

..............................

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3 years ago

Write equations for the initiation and propagation steps for the formation of dichloromethane by free radical

olya-2409 [2.1K]

Name of type of mechanism initiation step first propagation step second propagation step(ii) write an overall equation for the formation of dichloromethane from ... Best Answer: i) This is a free-radical substitution mechanism.

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3 years ago