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UNO [17]
3 years ago
9

the ordered pairs (0,-1),(1,0),(2,3),(3,8),(4,15) represent a function what is a rule that represents this function? Please help

!!
Mathematics
1 answer:
yarga [219]3 years ago
8 0

Answer:

The function rule is

f:  x\to \:  {x}^{2}  - 1

Step-by-step explanation:

The given ordered pairs are (0,-1), (1,0),(2,3),(3,8),(4,15)

We can observe the following pattern.

f(0) =  {0}^{2}  - 1 =  - 1

f(1) =  {1}^{2}  - 1 = 0

f(2) =  {2}^{2}  - 1 = 3

f(3) =  {3}^{2}  - 1 = 8

f(4) =  {4}^{2}  - 1 = 15

When we generalize this pattern, we obtain:

f(x) =  {x}^{2}  - 1

This is the function equation.

The function rule is

f:  x\to \:  {x}^{2}  - 1

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Answer:

  C.  postulate; theorem

Step-by-step explanation:

While a "given" is taken as true without proof, and a "problem" sometimes involves an assertion that can be proven, the answer choices involving these terms are not correct here.

The dictionary definitions of "postulate" and "theorem" apply. It is useful to learn the meaning of these terms so you can understand problems and descriptions that use them.

3 0
3 years ago
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Svetlanka [38]

Answer:

\sqrt[]{\frac{x+8}{4}}-3

Step-by-step explanation:

g(x)=4(x+3)^2-8

First rewrite g(x) as y

y=4(x+3)^2-8

Now swap y and x

x=4(y+3)^2-8

Add 8 on both sides.

x+8=4(y+3)^2-8+8

x+8=4(y+3)^2

Divide by 4.

\frac{x+8}{4} =\frac{4(y+3)^2}{4}

\frac{x+8}{4}=(y+3)^2

Extract the square root on both sides.

\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}

\sqrt[]{\frac{x+8}{4}}=y+3

Subtract 3 on both sides.

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4 0
2 years ago
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sergiy2304 [10]

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7 0
3 years ago
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Step-by-step explanation:

Method 1) Find a common factor between 15 and 30. For this problem, I'll pick 5. Divide both numbers by this common factor.

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Method 2) Find the greatest common factor between 15 and 30. The GCF is 15. Divide both numbers by the GCF.

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