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UNO [17]
3 years ago
9

the ordered pairs (0,-1),(1,0),(2,3),(3,8),(4,15) represent a function what is a rule that represents this function? Please help

!!
Mathematics
1 answer:
yarga [219]3 years ago
8 0

Answer:

The function rule is

f:  x\to \:  {x}^{2}  - 1

Step-by-step explanation:

The given ordered pairs are (0,-1), (1,0),(2,3),(3,8),(4,15)

We can observe the following pattern.

f(0) =  {0}^{2}  - 1 =  - 1

f(1) =  {1}^{2}  - 1 = 0

f(2) =  {2}^{2}  - 1 = 3

f(3) =  {3}^{2}  - 1 = 8

f(4) =  {4}^{2}  - 1 = 15

When we generalize this pattern, we obtain:

f(x) =  {x}^{2}  - 1

This is the function equation.

The function rule is

f:  x\to \:  {x}^{2}  - 1

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mihalych1998 [28]

Answer:

no -9/4 is irrational

Step-by-step explanation:

vacsusvvsjshsvsh plz give brainliest

3 0
3 years ago
Two competing sports equipment suppliers sell footballs at different prices. Supplier A charges $85 in shipping, and charges $2.
S_A_V [24]
Supplier A: $188.6
Supplier B: $221.6

I hope I helped but I honestly have no idea if I did. Anyway sorry if I didn't. Good luck.
7 0
3 years ago
What is the sum of the first 51 consecutive odd positive integers?
Angelina_Jolie [31]
We call:

a_{n} as the set of <span>the first 51 consecutive odd positive integers, so:

</span>a_{n} = \{1, 3, 5, 7, 9...\}

Where:
a_{1} = 1
a_{2} = 3
a_{3} = 5
a_{4} = 7
a_{5} = 9
<span>and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

</span>a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}
<span>
Then:

</span>a_{n} = a_{1} + (n-1)d
<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

</span>S_{k} = ( \frac{a_{1} +  a_{k}}{2}  ).k
<span>
Therefore, we need to find:
</span>a_{k} =  a_{51}  

Given that a_{1} = 1, then:

a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1

Thus:
a_{k} = a_{51} = 2(51)-1 = 101

Lastly:

S_{51} = ( \frac{1 + 101}{2} ).51 = 2601 

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3 years ago
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BabaBlast [244]
Try 147? it may be wrong but i though that with that type of thing the middle one is supposed to equal double the bottom.
8 0
3 years ago
Read 2 more answers
Hey guys happy holidays! any help is appreciated :)
aleksandr82 [10.1K]

9514 1404 393

Answer:

  yes

Step-by-step explanation:

The given line of reflection is a perpendicular bisector of every segment joining any figure point with its image. Hence the given image trapezoid is a reflection across the line of the given pre-image trapezoid.

__

For example, Line f is the perpendicular bisector of AA'.

7 0
2 years ago
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