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yawa3891 [41]
3 years ago
12

IF U CAN SOLVE THIS I LITERALLY LUV U ILL GIVE U BRAINLIEST 5 STARS AND A THANKSSS OMG PLS IN 10 MINUETSSS :c

Mathematics
1 answer:
gogolik [260]3 years ago
7 0

Answer:

determination and family

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Write the equation of a circle centered at the
Fudgin [204]

Answer:

(x+4)^2+(y+6)^2=100

Step-by-step explanation:

Given a circle centred at the point P(-4,-6) and passing through the point

R(2,2).

To find its equation, we follow these steps.

Step 1: Determine its radius, r using the distance formula

For point P(-4,-6) and R(2,2)

\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{Radius=}\sqrt{(2-(-4))^2+(2-(-6))^2} \\=\sqrt{(2+4))^2+(2+6)^2}\\=\sqrt{6^2+8^2}\\=\sqrt{100}\\Radius=10

Step 2: Determine the equation

The general form of the equation of a circle passing through point (h,k) with a radius of r is given as: (x-h)^2+(y-k)^2=r^2

Centre,(h,k)=P(-4,-6)

r=10

Therefore, the equation of the circle is:

(x-(-4))^2+(y-(-6))^2=10^2\\\\(x+4)^2+(y+6)^2=100

3 0
3 years ago
I’ll mark brainliest!! Please help:)
Neporo4naja [7]
I can’t see the pic more can u edit it ms make it more bigger lol
6 0
3 years ago
PLEASE HELP ME ........
vodka [1.7K]

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What is the expression equivalent to xy ^ 2/9
DochEvi [55]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili
pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0
1 year ago
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