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Mnenie [13.5K]
3 years ago
14

The refractive index of medium A is 1.54 and that of medium B is 2.12. Which statement is correct about this information?

Physics
2 answers:
Dominik [7]3 years ago
7 0
Out of the choices given, the statement that is correct about this information is a ray of light passing from medium A to B will bend toward the normal. The correct answer is C. 
Kruka [31]3 years ago
3 0

Answer:

C. a ray of light passing from medium A to B will bend toward the normal.

Explanation:

When a ray of light enters from one medium to another, it deviates from its path and bends away towards or away from the normal. The angle of incidence (i) and angle of refraction (r) are related by Snell's law:

\frac{sin i}{sin r} =\frac{n_2}{n_1}

The refracted ray bends away from normal when light enters from denser medium to rarer medium.

The refracted ray bends towards normal when light ray enters from rarer medium to denser medium.

In the given case, the refractive index of medium A is 1.54 and of B is 2.12. Ray of light enters from medium A to B i.e. from rarer medium to denser medium. Thus, the light ray would bend towards the normal when it enters medium B from A.

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Traumatic brain injury such as concussion results when the head undergoes a very large acceleration. Generally, an acceleration
miss Akunina [59]

Answer:

1728.42857143 m/s²

0.00155883061577 s

259.264285715 m/s²

0.0103922041051 s

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Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2gs\\\Rightarrow v=\sqrt{2gs+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 0.37+0^2}\\\Rightarrow v=2.69432737432\ m/s

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-2.69432737432^2}{2\times 2.1\times 10^{-3}}\\\Rightarrow a=-1728.42857143\ m/s^2

Magnitude of deceleration is 1728.42857143 m/s²

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-2.69432737432}{-1728.42857143}\\\Rightarrow t=0.00155883061577\ s

Time taken is 0.00155883061577 s

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-2.69432737432^2}{2\times 1.4\times 10^{-2}}\\\Rightarrow a=-259.264285715\ m/s^2

Magnitude of deceleration is 259.264285715 m/s²

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-2.69432737432}{-259.264285715}\\\Rightarrow t=0.0103922041051\ s

Time taken is 0.0103922041051 s

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It is less likely that the child will get injured if he/she falls on a carpeted floor.

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3 years ago
How much electromagnetic energy is contained in each cubic meter near the Earth's surface if the intensity of sunlight under cle
WITCHER [35]

Answer:

344.8 x10^-8J/m³

Explanation:

Using=> energy intensity/ speed oflight

= 1000/2.9x10^8

= 344.8 x10^-8J/m³

3 0
3 years ago
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