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spin [16.1K]
3 years ago
6

WILL GIVE BRAINLIEST TO THE CORRECT ANSWER

Physics
1 answer:
LenKa [72]3 years ago
4 0

Answer:

See the answers below.

Explanation:

We can solve both problems using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F =m*a

where:

F = force [N] (units of newtons)

m = mass = 1000 [kg]

a = acceleration = 3 [m/s²]

F = 1000*3\\F=3000[N]

And the weight of any body can be calculated by means of the mass product by gravitational acceleration.

W=m*g\\W=1000*9.81\\W=9810 [N]

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What is the correct explanation of Newton's Third Law of Motion?
viva [34]

Answer:

a

Explanation:

it explains the most, and it is the correct theorem

8 0
3 years ago
Read 2 more answers
A first order reaction, A -> products, has a rate reaction of .00250 Ms-1 when [A] = . 484 M. (a) What is the rate constant,
tamaranim1 [39]

Answer: a)  The rate constant, k, for this reaction is 0.00516s^{-1}

b) No t_{\frac{1}{2}} does not depend on concentration.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

A\rightarrow products

Given: Order with respect to A = 1

Thus rate law is:

a) Rate=k[A]^1

k= rate constant

0.00250=k[0.484]^1

k=0.00516s^{-1}

The rate constant, k, for this reaction is 0.00516s^{-1}

b) Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{2.303}{k}\log\frac{100}{50}

t_{\frac{1}{2}}=\frac{0.69}{k}

Thus t_{\frac{1}{2}} does not depend on concentration.

8 0
3 years ago
A 61 kg skier leaves the end of a ski-jump ramp with a velocity of 27 m/s directed 21° above the horizontal. Suppose that as a r
Harman [31]

Answer:

22kj

Explanation:

set h = 0 at the end of slide.

final height is -12m

initial condition will be Ui = 0

Ki = 1/2mv² = 1/2 x 61 x (27)² = 22234.5J

Final condition is Ui = mgh = 61 x 9.8 x -12 = -7173J

Ki = 1/2mv²

Ki= 1/2 x 61 x (16)² = 7808J

conservation energy says that

Ui + Ki = Uf +Kf +ΔEth

so ΔEth = Ui + Ki - Uf - Kf

ΔEth = 22234.5 - 7808 + 7173

ΔEth = 21600J

ΔEth =22Kj

7 0
3 years ago
Read 2 more answers
A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67
egoroff_w [7]

Answer:

6.22 N/m

Explanation:

From Hooke's law we deduce that F=kx where F is the applied force and k is the spring constant while x is the extension or compression of the spring. Making k the subject of the above formula then

k=\frac {F}{x}

We also know that the force F is equal to mg where m is the mass of an object and g is acceleration due to gravity hence substituting F with mg we get that

k=\frac {mg}{x}

Substituting m with 425 g which is equivalent to 0.425 kg and g with 9.81 then 0.67 for x we get that

k=\frac {mg}{x}=\frac {0.425\times 9.81}{0.67}=6.222761194 N/m\approx 6.22\ N/m

Therefore, the spring constant is approximately 6.22 N/m

3 0
3 years ago
Which of the following equations can be used to calculate the current in a circuit?
sashaice [31]

Answer:

I need a picture

Explanation:

please elaborate. I need to get brainliest so I have to answer questions and get them right so send a picture so I can see the equation.

6 0
3 years ago
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