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3 years ago

7

Is there a sound loud enough to kill a person ?

2 answers:

Svetllana [295]3 years ago

7 0

Yes, In space I believe go to the NASA website and search your question there.

shepuryov [24]3 years ago

6 0

In space there is. Items such as a supernova will instantly end your life.

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The Sun is expected to undergo hydrogen fusion for a total of _____ years. a million 10 million a billion 10 billion 100 billion

Elanso [62]

The correct answer is 10 billion years. The Sun is expected to undergo hydrogen fusion for a total of 10 billion years. The Sun generates its energy by nuclear fusion of hydrogen and produces helium nucleus. It fuses 620 million metric tons every second.

3 0

3 years ago

Read 2 more answers

6. A light ray strikes a reflective plane surface at an angle of 560 with the surface.

Zolol [24]

Answer:

deez nouts

Explanation:

5 0

2 years ago

The density of gold is 19.3 g cm³. What is the mass of a bar of gold in Kg that measures 6 cm x 4 cmx to 2 cm ?

klemol [59]

Answer: 0.9264 kg

Explanation: [I'll use "cc" for cubic centimeter, instead of cm^3.

The volume is 6cm*4cm*2cm = 48 cm^3 (cc).

Density of Au is 19.3 g/cc

Mass of gold = (48 cc)*(9.3 g/cc) = 926.4 grams Au

1 kg = 1,000 g

(926.4 grams Au)*(1 kg/1,000 g) = 0.9264 kg, 0.93 kg to 2 sig figs

At gold's current price of $57,500/kg, this bar is worth $53,268. Keep it hidden from your lab partner (and instructor).

3 0

2 years ago

If the intensity level by 15 identical engines in a garage is 100 dB, what is the intensity level generated by each one of these

insens350 [35]

To develop this problem it is necessary to apply the concepts related to Sound Intensity.

By definition the intensity is given by the equation

$\beta = 10Log(\frac{I}{I_0})$

Where,

I = Intensity of Sound

$I_0$ = Intensity of Reference

At this case we have that 15 engines produces 15 times the reference intensity, that is

$I= 15I_0$

And the total mutual intensity is 100 dB, so we should

$\beta = 100-10*log(\frac{15I_0}{I_0})$

$\beta = 100-10*log(15)$

$\beta = 100-11.76$

$\beta = 88.23dB$

Therefore each one of these engines produce D. 88dB.

5 0

3 years ago

Two long, straight wires both carry current to the right, are parallel, and are 25 cm apart. Wire one carries a current of 2.0 A

Artemon [7]

Answer:

x = 7.14 meters

Explanation:

It is given that,

Current in wire 1, $I_1=2\ A$

Current in wire 2, $I_2=5\ A$

Distance between parallel wires, r = 25 cm

Let at P point the net magnetic field equal to 0. The magnetic field at a point midway between the is given by :

$B=\dfrac{\mu_oI}{2\pi r}$

Let the distance is x from wire 1. So,

$\dfrac{I_1}{r}=\dfrac{I_2}{(0.25-r)}$

$\dfrac{2}{r}=\dfrac{5}{(25-r)}$

$x=\dfrac{50}{7}\ m$

x = 7.14 meters

So, the magnetic field will be 0 at a distance of 7.14 meters from wire 1. Hence, this is the required solution.

6 0

3 years ago