Answer:
t = 1130 s = 18.83 min
Explanation:
First, we will calculate the energy required to evaporate 500 g of water:
where,
E = Energy Required for evaporation of water =?
m = mass of water = 500 g = 0.5 kg
L = Latent heat of vaporization of water = 2.26 MJ/kg = 2260 KJ/kg
Therefore,
Now, we will calculate the time required:
where,
t = time = ?
P = Power of kettle = 1 KW
Therefore,
<u>t = 1130 s = 18.83 min</u>
Explanation:
Answer:
The time of Mars is 1.65 times larger on Mars than on Earth
Explanation:
The equation that describes the system is the final speed is equal to the speed minos the speed lost by the collision with the porhole
Vf = Vo - V pothole
B) let's transform the weight of free groin system and N international system
1 N = 0.2248 lb
2.8 lbs (1N / 0.2248lbs) = 12.5 N
c) Kinematic equations are the same in all inertial systems, Mars and Earth, so we can use the height equation, with zero initial velocity
Y = Vo t - ½ g t²
Y = - ½ g t²
t = √ 2Y / g
Mars
gm = 0.37g
gm = 0.37 9.8
gm = 3,626 m / s²
t = √( 2 1.9 / 3.626 )
t = 1.02 s
Earth
t = √( 2 1.9 / 9.8)
t = 0.62 s
To make the comparison of time we are the relationship between the two
tm / te = 1.02 / 0.62
tm / te = 1.65
The time of Mars is 1.65 times larger on Mars than on Earth
