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11111nata11111 [884]
4 years ago
7

A roller coaster car picks up speed as it rolls down the slope. As it starts down

Physics
1 answer:
vivado [14]4 years ago
4 0

Answer:

22 m/s

Explanation:

v(t) = Vo + at

v(3) = 4 + 6*3

v = 4 + 18

v = 22 m/s (almost 50 miles/hour)

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A particle with charge -5.60 nC is moving in a uniform magnetic field →B=−(1.25T) k The magnetic force on the particle is measur
chubhunter [2.5K]

Answer:

Explanation:

Force = q ( v x B)

- 5.6 x 10⁻⁹ (v x - 1.25 k )

- 3.4x 10⁻⁷i + 7.4 x 10⁻⁷j

Let v = ai+bj +ck

Force = - 5.6 x 10⁻⁹ [(ai+bj +ck) x - 1.25 k )]

= - 5.6 x 10⁻⁹ ( 1.25aj - 1.25bi )

= - 7 a j + 7 b i

( 7bi - 7aj ) x 10⁻⁹

Comparing with given force

7b x 10⁻⁹ b = - 3.4 x 10⁻⁷

b = - 48.57

- 7 a x 10⁻⁹ = 7.4 x 10⁻⁷

a = - 105.7

velocity

= -105.7 i - 48.57 j + ck

b ) Component along k can not be obtained .

c ) v . F = ( -105.7 i - 48.57 j + ck ) . −(3.40×10−7N) ˆı +(7.40×10−7N) ˆȷ

= 105.7 x 3.4 x 10⁻⁷ - 48.57 x 7.4 x 10⁻⁷

= 359.38 x 10⁻⁷ - 359.38 x 10⁻⁷

=0

angle between v and F = 90 degree

4 0
3 years ago
A student is experimenting with some insulated copper wire and a power supply. She winds a single layer of the wire on a tube wi
OverLord2011 [107]

Answer:

P=214.7187\,W

Explanation:

Given that:

Diameter of the solenoid, D=10\,cm=0.1\,m

length of the solenoid, L=90\,cm=0.9\,m

diameter of the wire, d=0.1\,cm=10^{-3}\,m

magnetic field at the center of the solenoid, B=7.4\times 10^{-3}\,T

<u>Now we need the no. of turns incorporated in the length of 90 cm:</u>

N=\frac{Length\,\,of\,\,solenoid}{diameter\,\,of\,\, wire}

N=\frac{L}{d}

N=\frac{0.9}{10^{-3}}

N=900\,\,turns

For solenoids we have:

B=\mu.n.I ...............................(1)

where:

\mu=permeability of the medium

n = no. of turns per unit length

I = current in the coil

So,

n=\frac{900}{0.9}

n=1000\,turns\,.\,m^{-1}

Now putting the respective values in the eq. (1)

7.4\times 10^{-3}=4\pi\times10^{-7}\times 1000\times I

I=5.8887\,A

  • For copper we have resistivity:
  • \rho=1.72\times 10^{-8}\, \Omega.m

We know that resistance is given by:

R=\rho.\frac{l}{a} .....................................(2)

where:

l = length of the conducting wire

a = cross sectional area of the conducting wire

<u>Now we need the length (l) of the wire:</u>

Circumference of the solenoid,

C=\pi.D

C=0.1\pi\,m

\therefore l=C\times N

l=90\pi\,m

&

<u>Cross-sectional area of wire:</u>

a=\pi.\frac{d^2}{4}

a=\pi. \frac{(10^{-3})^2}{4}\,m^2

<u>Resistance from eq. (2):</u>

R=1.72\times 10^{-8}\times \frac{90\pi}{\pi. \frac{(10^{-3})^2}{4}}

R=6.192 \,\Omega

  • For power we have:

P=I^2.R

P=5.8887^2 \times 6.192

P=214.7187\,W

6 0
3 years ago
A car travels east at 11 km/h for 3.1 hours and west at 11 km/h for 5.3 hours. What distance (in km) does it travel in this time
Verizon [17]

Answer:

45.1/3× 3.1/2 + 50.1/2× 2.1/2

=136/3. 7/2.+ 101/2× 5/2

=952/6 + 505/2

=( 952+ 1515)/6

=411.16

Explanation:

Make sure to read and go with it

4 0
3 years ago
Read 2 more answers
A speaker generates a continuous tone of 440 Hz. In the drawing, sound travels into a tube that splits into two segments, one lo
chubhunter [2.5K]

Answer:

The minimum difference between the lengths of the two tubes should be 0.385 meters.

Explanation:

As we known that for any two waves to arrive in phase at any point the difference in the path traveled by the waves should be an integral multiple of the wavelength of the wave.

Mathematically we can write:

\Delta x=n\frac{\lambda }{2}

For the given wave we have

\lambda =\frac{v}{\nu }

Applying values we get

\lambda =\frac{339}{440 }=0.77m

Thus the minimum difference in the lengths of the tubes can be obtained by putting the value of n = 1

\therefore \Delta x=1\times \frac{0.77}{2}=0.385m

7 0
4 years ago
A student says that a speed of 50 m/s is faster than a speed of 140 km/h because the number is bigger. What would you say to the
denis23 [38]

Yes you are right but sometimes just because a number is  bigger doesnt always make it so.

5 0
3 years ago
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