The light from the Sun heats a metal surface

Electromagnetic force is carried between particles of matter by particles named what

xz_007 [3.2K]

Answer:

gluons

Explanation:

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8 0

4 years ago

you push a 51 kg box with a force of 485 N. the friction force on the box is 232 N. calculate the acceleration of the crate.

vichka [17]

Answer:

a = 4.96 m/s²

Explanation:

Given,

The mass of the box, m = 51 Kg

The magnitude of the applied force, Fₐ = 485 N

The friction force on the box, Fₓ = 232 N

The net force acting on the box is,

F = Fₐ - Fₓ

Substituting the given values in the above equation

F = 485 - 232

= 253 N

The acceleration of the crate is given by

a = F/m

= 253 / 51

= 4.96 m/s²

Hence, the acceleration of the crate is, a = 4.96 m/s²

3 0

3 years ago

A 51.0 kg cheetah accelerates from rest to its top speed of 31.7 m/s. HINT (a) How much net work (in J) is required for the chee

andrey2020 [161]

(a) $2.56\cdot 10^4 J$

The work-energy theorem states that the work done on the cheetah is equal to its change in kinetic energy:

$W= \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$

where

m = 51.0 kg is the mass of the cheetah

u = 0 is the initial speed of the cheetah (zero because it starts from rest)

u = 31.7 m/s is the final speed

Substituting, we find

$W=\frac{1}{2}(51.0 kg)(31.7 m/s)^2 - \frac{1}{2}(51.0 kg)(0)^2=2.56\cdot 10^4 J$

(b) 6.1 cal

The conversion between calories and Joules is

1 cal = 4186 J

Here the energy the cheetah needs is

$E=2.56\cdot 10^4 J$

Therefore we can set up a simple proportion

$1 cal : 4186 J = x : 2.56\cdot 10^4 J$

to find the equivalent energy in calories:

$x=\frac{(1 cal)(2.56\cdot 10^4 J)}{4186 J}=6.1 cal$

3 0

3 years ago

Match the layer of Earth with its characteristic.

mote1985 [20]

Answer:

Explanation:

The Asthenosphere -- drives the movement in the plates

It is a weak and flexible part of the upper mantle of the planet Earth.

It is located below the lithosphere. The depth of it is between 200 and 80 kilometers below the surface. It is usually solid but in some regions it is fluid. The temperature dictates the thickness of the Asthenosphere.

The Core -- the hottest layer of the Earth.

The inner Core of the Earth is a layer that's located in the core of it. By definition, it is a rock-hard ball that has the radius of 1,220 kilometers, making it 20% of the Earth's radius and 70% of the Moon's radius. The samples are not discovered. It is believed that it has the composition of iron-nickel infusion along with other elements. The temperature is appx. 5430 °C, which is similar to the temperature of the surface of the Sun.

Mesosphere -- contains the lower mantle

By definition, it comes from the Greek word mesos, which means '' middle ''.

It is the third layer of the Earth. It is located above the stratosphere and below the thermosphere. The higher the altitude, the lower the temperature. It ends in the coldest part of the Earth, Mesopause. And it begins at the Stratosphere.

Lithosphere -- contains the tectonic plates

By the definition, it is also a word that came from the Greek language. It comes from the word '' lithos '' which means '' rocky ''.

It is a hard, outer part of the Earth.

On the planet Earth, it is made out of the crust of the upper mantle. The rocks from the Lithosphere are elastic.

They are two types of Lithosphere -- the oceanic Lithosphere and Continental Lithosphere.

6 0

3 years ago

Read 2 more answers

A spaceship is traveling through deep space towards a space station and needs to make a course correction to go around a nebula.

expeople1 [14]

Answer:

Magnitude = 3.64 × $10^6$

စ = 43.9°

Explanation:

given data

ship to travel = 1.7 × $10^6$ kilometers

turn = 70°

travel an additional = 2.7 × $10^6$ kilometers

solution

we will consider here

Px = 1.7 × $10^6$

Py = 0

Qx =2.7 × $10^6$ cos(70)

Qy= 2.7 × $10^6$ sin(70)

so that

Hx = Px + Qx ............1

Hx = 2.62 × $10^6$

and

Hy = Py + Qy ..........2

Hy = 2.53 × $10^6$

so Magnitude = $\sqrt{((2.62 \times 10^6 )^2+(2.53 \times 10^6)^2)}$

Magnitude = 3.64 ×

so direction will be

tan စ = Hy ÷ Hx ......................3

tan စ = $\frac{2.53}{2.62}$

tan စ = 0.9656

စ = 43.9°

3 0

3 years ago