Answer:
a) 145.6kgm^2
b) 158.4kg-m^2/s
c) 0.76rads/s
Explanation:
Complete qestion: a) the rotational inertia of the merry-go-round about its axis of rotation
(b) the magnitude of the angular momentum of the child, while running, about the axis of rotation of the merry-go-round and
(c) the angular speed of the merry-go-round and child after the child has jumped on.
a) From I = MK^2
I = (160Kg)(0.91m)^2
I = 145.6kgm^2
b) The magnitude of the angular momentum is given by:
L= r × p The raduis and momentum are perpendicular.
L = r × mc
L = (1.20m)(44.0kg)(3.0m/s)
L = 158.4kg-m^2/s
c) The total moment of inertia comprises of the merry- go - round and the child. the angular speed is given by:
L = Iw
158.4kgm^2/s = [145kgm^2 + ( 44.0kg)(1.20)^2]
w = 158.6/208.96
w = 0.76rad/s
Answer:
Explanation:
Given that
Length= 2L
Linear charge density=λ
Distance= d
K=1/(4πε)
The electric field at point P
So
Now by integrating above equation
Yes. On a circular path, the direction of motion is constantly changing. Change of direction is acceleration, even at constant speed.
Answer:
the mass of a mercury with volume of 263mL = 3559.3 g or 3.56 kg
Explanation:
given:
263 mL liquid mercury
find:
What is the mass of mercury
we know that the density of mercury = 13.5336 g/mL.
now, calculate the mass = volume x density
plugin values into the formula
mass = 263 mL x 13.5336 g/mL.
mass = 3559.3 g or 3.56 kg
therefore,
the mass of a mercury with volume of 263mL = 3559.3 g or 3.56 kg
