1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikklg [1K]
3 years ago
15

Three charges 1.5*10-6, 3*10-6, -3*10-6 are placed at three vertices of an equilateral triangle of side 30cm. Find the net force

acting on 1.5*10-6 due to the other two

Physics
2 answers:
gulaghasi [49]3 years ago
5 0

Answer:

F = 0N

Explanation:

The force between two charges is given by

F=k\frac{q_1q_2}{r^2}

where r is the distance between the charges and K is the Coulomb's constant

(k=8-89*10^9Nm^2/C^2)

The force in the first charge is only the sum of the forces due to the other charges. Hence we have

F_T=F_1+F_2=k\frac{q_2q_1}{r^2}+k\frac{q_3q_1}{r^2}

F_T=(8.89*10^9\frac{Nm^2}{C^2})\frac{(3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}+(8.89*10^9\frac{Nm^2}{C^2})\frac{(-3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}\\\\F_T=0.445N-0.445N=0N

Ft=0N

Hope this helps!!

larisa86 [58]3 years ago
5 0

Answer:

Explanation:

Check attachment for free body diagram.

Fnet =F12 + F13

Therefore,

The force of attraction between two charges is given as

F12 = kq1q2/r²

F12=9×10^9×1.5 ×10^-6×3×10^-6/0.3²

F12 = 0.45N

Also,

F13 = kq1q3/r²

F13=9×10^9×1.5 ×10^-6×3×10^-6/0.3²

F13 = 0.45N

From the diagram we notice that F12 is acting between positive x-axis and y axis

F12 = F12Sin30 •i + F12 Cos30 •j

F12 = 0.45Sin30 •i + 0.45Cos30 •j

F12 = 0.225 •i + 0.39 •j N

F13 is acting between positive x axis and negative y axis

Then,

F13 = F12Sin30 •i — F12 Cos30 •j

F13 = 0.45Sin30 •i — 0.45Cos30 •j

F13 = 0.225 •i — 0.39 •j N

Then,

Fnet = F12 + F13

Fnet = 0.225 •i + 0.39 •j + N0.225 •i - 0.39 •j N

Fnet = 0.45 •i N

The net force has a magnitude of 0.45N and it is acting on the positive x axis

Then it direction is

X = arctan(y/x)

X = arctan(0)

X = 0°

You might be interested in
Is Algae Biotic or Abiotic?
muminat
It’s biotic because it’s a living thing
Abiotic would be like a rock non living things
Answer:Biotic
4 0
2 years ago
Read 2 more answers
After watching a show about submarines, Jamil wants to learn more about the oceans. Which question could be answered through sci
Georgia [21]
The best question that could prompt a scientific investigation is: <u>What substances dissolve in ocean water?</u> 

This way the person experimenting can use several variables and make observations. Upon making observations, the person can be able to gather as much data as he can in order to answer the original question that he asked.
7 0
3 years ago
Read 2 more answers
Two ropes have equal length and are stretched the same way. The speed of a pulse on rope 1 is 1.4 times the speed on rope 2. Par
kondor19780726 [428]

Answer:

m1/m2 = 0.51

Explanation:

First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:

V = √F/u

This is the equation that describes the relation between speed of a pulse and a force exerted on it.

the value of "u" is:

u = m/L

Where m is the mass of the rod, and L the length.

Now, for the rod 1:

V1 = √F/u1 (1)

rod 2:

V2 = √F/u2 (2)

Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:

1.4V2 = √F/u1 (3)

Replacing (2) in (3):

1.4(√F/u2) = √F/u1 (4)

Now, let's solve the equation 4:

[1.4(√F/u2)]² = F/u1

1.96(F/u2) =F/u1

1.96F = F*u2/u1

1.96 = u2/u1 (5)

Now, replacing the expression of u into (5) we have the following:

1.96 = m2/L / m1/L

1.96 = m2/m1 (6)

But we need m1/m2 so:

1.96m1 = m2

m1/m2 = 1/1.96

m1/m2 = 0.51

5 0
3 years ago
Assuming that Albertine's mass is 60.0 kg , for what value of μk, the coefficient of kinetic friction between the chair and the
makvit [3.9K]

Answer:

\mu_k=0.101

Explanation:

It is given that,

Mass of Albertine, m = 60 kg

It can be assumed, the spring constant of the spring, k = 95 N/m

Compression in the spring, x = 5 m

A glass sits 19.8 m from her outstretched foot, h = 19.8 m

When she just reach the glass without knocking it over, a force of friction will also act on it. Using the conservation of energy for the spring mass system such that,

\dfrac{1}{2}kx^2=\mu_k mgh

\mu_k=\dfrac{kx^2}{2mgh}

\mu_k=\dfrac{95\times (5)^2}{2\times 60\times 9.8\times 19.8}

\mu_k=0.101

So, the coefficient of kinetic friction between the chair and the waxed floor is 0.101. Hence, this is the required solution.

3 0
3 years ago
A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness
Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

\sigma_h = \frac{Pd}{2t}

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

\sigma_l = \frac{Pd}{4t}

The letters have the same meaning as before.

Then he hoop stress would be,

\sigma_h = \frac{Pd}{2t}

\sigma_h = \frac{75 \times 8}{2\times 0.25}

\sigma_h = 1200psi

And the longitudinal stress would be

\sigma_l = \frac{Pd}{4t}

\sigma_l = \frac{75\times 8}{4\times 0.25}

\sigma_l = 600Psi

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

\tau_{max} = \frac{\sigma_h}{2}

\tau_{max} = \frac{1200}{2}

\tau_{max} = 600Psi

Therefore the maximum shear stress in the pressure vessel when it is subjected to this pressure is 600Psi

6 0
3 years ago
Other questions:
  • Is it true the atoms in sulphur liquid are the same as the atoms in solid sulphur?
    7·1 answer
  • The student makes a drawing of a carbon atom. Which of these should the student show in the nucleus of the atom?
    15·1 answer
  • A long line carrying a uniform linear charge density+50.0μC/m runs parallel to and 10.0cm from the surface of a large, flat plas
    7·1 answer
  • The three factors that determine the amount of potential energy in an object are ________, ___________, and _________.
    12·2 answers
  • Need help today please​
    5·1 answer
  • Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−370 kJ X2+2Z2⟶2XZ2ΔH2=−120 kJ 2Y2+Z2⟶2Y2ZΔH3=−270 kJ Calculate the change in
    5·1 answer
  • What is the unit of G in the F=Gm1m2/r^2​
    8·2 answers
  • What do you make when you dissolve sugar in water?
    10·1 answer
  • Of the following reactions, which is a fusion reaction?
    7·1 answer
  • 2 A box of mass 3 kg is initially at rest. Find the kinetic energy acquired by the box if
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!