Explanation:the answer is wrist
Answer:
3.78 m on the left side of the seesaw
Explanation:
The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:
(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r
Solve for r, and you get 3.78 on the left side.
Hope this helps!
Answer:
Fav = -12209 N
Explanation:
let p1 be the initial momentum of the ball and p2 be the final momentum of the ball. let v1 be the initial velocity of the ball and v2 be the final velocity of the ball.
From Newton's second law of motion, we get that the avarage force acting on the ball is given by:
Fav = Δp/t
= (p2 - p1)/t
= m(v2 - v1)/t
= [(145×10^-3)(-45.3 - 38.9)/(1×10^-3)
= - 12209 N
Therefore, the average force applies on the ball by tha bat is 12209 in the direction opposite to the balls initial direction.
-- Find the mass of all the pieces before the reaction.
-- Find the mass of all the pieces after the reaction.
-- Find the difference . . . (mass before) minus (mass after)
-- If any mass is missing, either you lost track of it, or else
it was converted to energy.
How much energy ?
(the missing mass) times c² .
