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Blizzard [7]
3 years ago
15

Shaun is 68 miles away from Keegan. They are traveling towards each other. If Keegan travels 7 mph faster than Shaun and they me

et after 4 hours, how fast was each traveling?
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:vs=5mph  , vk=7+vs=12mph

Explanation: kinematics with constant speed

(shaun) xs = 0 + vs*t

(keegan)  xk= 68 - vk*t

they meet after t= 4hours (xs=xk):

vs*t=  68-vk*t

but we know that vk=7+vs ( keegan faster) replacing:

vs*4= 68-(7+vs)*4

solving vs=5mph  , vk=7+vs=12mph

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Frequency is measured in units called?
irina1246 [14]
The frequency, f, of a wave is the number of waves passing a point in a certain time. We normally use a time of one second, so this gives frequency the unit hertz (Hz), since one hertz is equal to one wave per second.
5 0
3 years ago
You are traveling at 100 km/hr to make it to work on time. You have to be to work in .25 hr or you will be late. You have 16 km
alexgriva [62]

Answer: Yes

Explanation:

Velocity V is defined as the distance traveled d in a specific time t:

V=\frac{d}{t}

If you are traveling at V=100 km/h a distance d=16 m, then the time it will take you to be at work is:

t=\frac{d}{V}=\frac{16 km}{100 km/h}

t=0.16 h

This means you will make it on time, because this time is less than 0.25 h.

4 0
4 years ago
Three children are riding on the edge of a merry-go-round that is 100 kg, has a 1.60-m radius, and is spinning at 20.0 rpm. The
Kay [80]

Answer:

25.33 rpm

Explanation:

M = 100 kg

m1 = 22 kg

m2 = 28 kg

m3 = 33 kg

r = 1.60 m

f = 20 rpm

Let the new angular speed in rpm is f'.

According to the law of conservation of angular momentum, when no external torque is applied, then the angular momentum of the system remains constant.

Initial angular momentum = final angular momentum

(1/2 x M x r^2 + m1 x r^2 + m2 x r^2 + m3 x r^2) x ω =

                                  (1/2 x M x r^2 + m1 x r^2 + m3 x r^2 ) x ω'

(1/2 M + m1 + m2 + m3) x 2 x π x f = (1/2 M + m1 + m3) x 2 x π x f'

( 1/2 x 100 + 22 + 28 + 33) x 20 = (1/2 x 100 + 22 + 33) x f'

2660 = 105 x f'

f' = 25.33 rpm

8 0
3 years ago
Is a measure of how closely packed together the particles of matter are in a specific volume
Mnenie [13.5K]

Answer:

Density is an important physical property of matter. It reflects how closely packed the particles of matter are. When particles are packed together more tightly, matter has greater density.

Explanation:

5 0
3 years ago
A circular rod with a gage length of 3.5 mm and a diameter of 2.8 cmcm is subjected to an axial load of 68 kN . If the modulus o
Crank

To solve this problem, we will apply the concepts related to the linear deformation of a body given by the relationship between the load applied over a given length, acting by the corresponding area unit and the modulus of elasticity. The mathematical representation of this is given as:

\delta = \frac{PL}{AE}

Where,

P = Axial Load

l = Gage length

A = Cross-sectional Area

E = Modulus of Elasticity

Our values are given as,

l = 3.5m

D = 0.028m

P = 68*10^3 N

E = 200GPa  

A = \frac{\pi}{4}(0.028)^2 \rightarrow 0.0006157m^2

Replacing we have,

\delta = \frac{PL}{AE}

\delta = \frac{( 68*10^3)(3.5)}{(0.0006157)(200*10^9)}

\delta = 0.001932m

\delta = 1.93mm

Therefore the change in length is 1.93mm

7 0
3 years ago
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