1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
romanna [79]
2 years ago
12

Bob walks 290 m south, then jogs 630 m southwest, then walks 290 m in a direction 26 ∘ east of north.

Physics
1 answer:
solong [7]2 years ago
3 0

whos spying on bob O.o


You might be interested in
Wheel A has a radius of R and wheel B has a radius of 2R. Wheel A has all the mass at the rim, while wheel B has the mass unifor
azamat

Answer:

Wheel A.

Explanation:

The lesser the moment of inertia, the greater the angular acceleration. Then, the moments of inertia of each wheel are described below:

Wheel A

I_{A} = M\cdot R^{2}

Wheel B

I_{B} = \frac{1}{2}\cdot M \cdot (2\cdot R)^{2}

I_{B} = 2\cdot M\cdot R^{2}

The wheel A accelerates faster in response to the torque.

3 0
2 years ago
How can we balance the use of fossil fuels with other forms of energy?
KiRa [710]
We can use renewable sources
4 0
3 years ago
When a mass M hangs from a vertical wire of length L, waves travel on this wire with a speed V. What will be the speed of these
Zigmanuir [339]

Answer:

a)  v = 0.7071 v₀, b) v= v₀, c)  v = 0.577 v₀, d)   v = 1.41 v₀, e)  v = 0.447 v₀

Explanation:

The speed of a wave along an eta string given by the expression

          v = \sqrt{ \frac{T}{ \mu } }

where T is the tension of the string and μ is linear density

a) the mass of the cable is double

          m = 2m₀

let's find the new linear density

          μ = m / l

iinitial density

          μ₀ = m₀ / l

final density

          μ = 2m₀ / lo

          μ = 2 μ₀

we substitute in the equation for the velocity

initial            v₀ = \sqrt{ \frac{T_o}{ \mu_o} }

with the new dough

                    v = \sqrt{ \frac{T_o}{ 2 \mu_o} }

                    v = 1 /√2  \sqrt{ \frac{T_o}{ \mu_o} }

                    v = 1 /√2 v₀

                    v = 0.7071 v₀

b) we double the length of the cable

If the cable also increases its mass, the relationship is maintained

              μ = μ₀

   in this case the speed does not change

c) the cable l = l₀ and m = 3m₀

we look for the density

           μ = 3m₀ / l₀

           μ = 3 m₀/l₀

           μ = 3 μ₀

            v = \sqrt{ \frac{T_o}{ 3 \mu_o} }

            v = 1 /√3  v₀

            v = 0.577 v₀

d) l = 2l₀

            μ = m₀ / 2l₀

            μ = μ₀/ 2

           v = \sqrt{ \frac{T_o}{ \frac{ \mu_o}{2} } }

           v = √2 v₀

            v = 1.41 v₀

e) m = 10m₀ and l = 2l₀

we look for the density

             μ = 10 m₀/2l₀

             μ = 5 μ₀

we look for speed

             v = \sqrt{ \frac{T_o}{5 \mu_o} }

             v = 1 /√5  v₀

             v = 0.447 v₀

5 0
2 years ago
The two pucks of equal mass did not move linearly (they came to a stop) after the collision due to the conservation of linear mo
weeeeeb [17]

Compared to the pucks given, the pair of pucks will rotate at the same rate.

Answer: Option A

<u>Explanation:</u>

The law of conservation of the angular momentum expresses that when no outer torque follows upon an article, no difference in angular momentum will happen.  At the point when an item is turning in a shut framework and no outside torques are applied to it, it will have no change in angular momentum.

The conservation of the angular momentum clarifies the angular quickening of an ice skater as she brings her arms and legs near the vertical rotate of revolution.  In the event, that the net torque is zero, at that point angular momentum is steady or saved.  

By twice the mass yet keeping the speeds unaltered, also twice the angular momentum's to the two-puck framework.  Be that as it may, we likewise double the moment of inertia. Since L=I \times \omega, the turning rate of the two-puck framework must stay unaltered.

4 0
3 years ago
During a trial run, race car A starts from rest and accelerates uniformly along a straight level track for a particular interval
kondor19780726 [428]
Answer: car B has travelled 4times as far as Car A

d=vi*t+1/2at^2

No initial velocity so equation becomes;

d=1/2at^2 and the acceleration is the same between both only time is different;

Car A d=1/2a(1)^2

Car B d=1/2a(2)^2

Car A d= 1^2=1

Car B d= 2^2=4

Car B d=4*Car A

So car B has travelled 4 times as far as car A
5 0
2 years ago
Other questions:
  • A space shuttle can accelerate at a rate of 2.5m/s squared. Given that, and the fact that the engines of the space shuttle can p
    14·2 answers
  • A 40.1 g object is attached to a horizontal spring with a spring constant of 11.9 N/m and released from rest with an amplitude o
    13·1 answer
  • What is a transverse wave
    8·1 answer
  • What is the efficiency of the machine in Figure 7.2 if the weight of the box is 200 N and required 98 N of effort Force?
    13·1 answer
  • A speeding car is going 72 mi/hr. The driver hits the brakes to slow the car down to the 45 mi/hr speed limit. The car has a mas
    5·1 answer
  • Where in the body are nitrogen compounds found?
    5·2 answers
  • Which element is represented by the atomic model below?
    10·1 answer
  • The speed of propagation of electrical signals in a nerve cell depends on the diameter of the axon (nerve fiber). If the nerve c
    7·1 answer
  • Can somebody help meeeee...?​
    8·1 answer
  • •Accordingto the graph, how many dark-colored moths existed in year 8?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!