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Molodets [167]
3 years ago
12

If the maximum time between the emitted and received pulse is 1/ 10 second, what is the farthest distance you could measure with

the sensor? (This question requires units.)
Physics
1 answer:
Allisa [31]3 years ago
7 0

Answer:

d = 2,998 10⁷ m

Explanation:

The speed of an electromagnetic wave is the speed of light

      c = 2,998 10⁸ m / s

This speed is in a vacuum, when the light is in a material medium, its speed is lower than this, even when the order of magnitude is maintained.

Since the speed of a wave is constant, we can use the kinematic relationship

       c = d / t

       d = c t

Let's calculate

      d = 2,998 108 0.1

      d = 2,998 10⁷ m

in the vacuum or air

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Answer:

Acceleration of the bullet will be 1778835.6 m/sec^2      

Explanation:

We have given length of the barrel refile s= 0.855 m

When the bullet leaves the muzzle its velocity is 553 m/sec

So final velocity v = 553 m/sec

Initial velocity will be 0 that is u = 0 m/sec

According to third equation of motion v^2=u^2+2as

553^2=0^2+2\times a\times 0.855

a=178835.6m/sec^2

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A person observing a flame is interested in the types of electromagnetic waves with slightly shorter and slightly longer wavelen
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Answer:

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3 years ago
The total surface area of the human body is 1.20 m2 and the surface temperature is 30∘C=303∘K. If the surroundings are at a temp
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Q =Ae\sigma T_2^4-Ae\sigma T_1^4

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