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Molodets [167]
3 years ago
12

If the maximum time between the emitted and received pulse is 1/ 10 second, what is the farthest distance you could measure with

the sensor? (This question requires units.)
Physics
1 answer:
Allisa [31]3 years ago
7 0

Answer:

d = 2,998 10⁷ m

Explanation:

The speed of an electromagnetic wave is the speed of light

      c = 2,998 10⁸ m / s

This speed is in a vacuum, when the light is in a material medium, its speed is lower than this, even when the order of magnitude is maintained.

Since the speed of a wave is constant, we can use the kinematic relationship

       c = d / t

       d = c t

Let's calculate

      d = 2,998 108 0.1

      d = 2,998 10⁷ m

in the vacuum or air

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A helium weather balloon is filled to a volume of 219 m3 on the ground, where the pressure is 754 torr and the temperature is 29
Novosadov [1.4K]

Answer:

V_2 = 606.9 m^3

Explanation:

By ideal gas equation law we know that

PV = nRT

now we know that when balloon rises to certain level then the number of moles will remains same

so we can say

n_1 = n_2

\frac{P_1V_1}{RT_1} = \frac{P_2V_2}{RT_2}

now plug in all data to find the final volume of the balloon

\frac{754\times 219}{R(298)} = \frac{210 \times V_2}{R(230)}

V_2 = \frac{230\times 754 \times 219}{210 \times 298}

V_2 = 606.9 m^3

8 0
3 years ago
2. A 75 kg runner accelerates from 0.00 m/s to 10.0 m/s in 1.5 seconds.
raketka [301]
A :-) A.a.) Given - u = 0.00 m/s
v = 10.0 m/s
t = 1.5 sec
m = 75 kg
Solution -
a = v - u by t
a = 10 - 0 by 1.5
a = 10 by 1.5
a = 6.6 m/s^2

A.b.) sorry ! I don’t no how to do this question
3 0
3 years ago
A block of mass 20 kg sits on a ramp with an angle of 31 degrees above the horizontal. Assuming no friction, how fast will the b
Artyom0805 [142]

Answer:

2.98 m/s^2

Explanation:

I have done this before and it was a question on my physics test

4 0
4 years ago
Read 2 more answers
How do you calculate acceleration
AfilCa [17]
A=f/m
Example a=10/2
A=5
7 0
4 years ago
Read 2 more answers
Using equations, determine the temperature, pressure and density of the air for a aircraft flying at 19.5 km. Is this aircraft s
Viefleur [7K]

Answer:

a) - 72.5°c

b) pressure = 3625.13 Pa

c) density =  0.063 kg/m^3

d) it is a subsonic aircraft

Explanation:

a) Determine Temperature

Temperature at 19.5 km ( 19500 m )

T = -131 + ( 0.003 * altitude in meters )

  =  -131 + ( 0.003 * 19500 ) = - 72.5°c

b) Determine pressure and density at 19.5 km altitude

Given :

Po (atmospheric pressure at sea level )  = 101kpa

R ( gas constant of air ) = 0.287 KJ/Kgk

T = -72.5°c ≈ 200.5 k

pressure = 3625.13 Pa

hence density = 0.063 kg/m^3

attached below is the remaining part of the solution

C) determine if the aircraft is subsonic or super sonic

Velocity ( v ) = \sqrt{CRT}  =  \sqrt{1.4*287*200.5 } = 283.8 m/s

hence it is a subsonic aircraft

4 0
3 years ago
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