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Ivanshal [37]
3 years ago
5

Maisie drags a 1kg mass along a table with a Newton meter so that it accelerates at 0.25 m/s. The Newton-meter reads 0.4N, calcu

late the force of friction between the mass and the table
Physics
1 answer:
Temka [501]3 years ago
7 0
Applying one newton of force to an object of 1 kg accelerates it by 1 meter per second

maisie applied .4 newtons to the block, so it should be accelerating at .4 m/s
but it actually accelerated at .25 m/s or .25 newtons reached the block

the difference in force applied and force received is .15, which is the force of friction because that's how much force it stopped from reaching the block
force of friction is .15 newtons
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Guys please help me ​
Likurg_2 [28]

Answer:

1)t=2.26\: s

2)S=33.9\: m

3)v=26.77\: m/s

4)\alpha=55.92

Explanation:

1)

We can use the following equation:

y_{f}=y_{0}+v_{iy}t-0.5*g*t^{2}

Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.

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2)

The equation of the motion in the x-direction is:

v_{ix}=\frac{S}{t}

15=\frac{S}{2.26}

S=33.9\: m

3)

The velocity in the y-direction of the stone will be:

v_{fy}=v_{iy}-gt

v_{fy}=0-(9.81*2.26)

v_{fy}=-22.17\: m/s

Now, the velocity in the x-direction is 15 m/s then the velocity will be:

v=\sqrt{v_{x}^{2}+v_{fy}^{2}}=\sqrt{15^{2}+(-22.17)^{2}}

v=26.77\: m/s

4)

The angle of this velocity is:

tan(\alpha)=\frac{22.17}{15}

\alpha=tan^{-1}(\frac{22.17}{15})

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Then α=55.92° negative from the x-direction.

I hope it helps you!

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