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a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2
<span>= 2.40 x 10-3 N
b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
Explanation:
Given that,
Object-to-image distance d= 71 cm
Image distance = 26 cm
We need to calculate the object distance
We need to calculate the focal length
Using formula of lens
put the value into the formula
The focal length of the lens is 35.52.
(B). Given that,
Object distance = 95 cm
Focal length = 29 cm
We need to calculate the distance of the image
Using formula of lens
Put the value in to the formula
We need to calculate the magnification
Using formula of magnification
The magnification is 0.233.
The image is virtual.
Hence, This is the required solution.
Answer:
B. Mechanical energy= 50J+30J=80J
<h3>
Answer:</h3>
30.4 km/hr
<h3>
Explanation:</h3>
<u>We are given</u>;
- Speed in the first 2 hours as 25 km/hr
- Speed in the next 3 hours as 34 km/hr
We are required to determine the average velocity in km/hr
- To get the average velocity we divide total distance by total time.
- Thus, we need to determine the total distance
Distance = Speed × time
Distance covered in the first 2 hours;
= 25 km/hr × 2 hours
= 50 km
Distance in the next 3 hours
= 34 km/hr × 3 hours
= 102 km
Therefore, total distance = 50 km + 102 km
= 152 km
Total time = 2 hrs + 3 hrs
= 5 hours
Therefore;
Average speed = 152 km ÷ 5 hours
= 30.4 km/hr
Thus, the average speed is 30.4 km/hr
