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Citrus2011 [14]
1 year ago
15

ill in the missing numbers along the sides of the triangle so that it contains each of the numbers from through exactly once. ​

furthermore, each side of the triangle should contain four numbers whose sum is .
Mathematics
1 answer:
mihalych1998 [28]1 year ago
5 0

Each side of the triangle should contain four numbers whose sum is 28.

3+5+9+11=28

3+10+8+7=28

11+6+9+7=28

The pain of numbers that can be used for A and B is [5,9] The pain of numbers that can be used for C and D is [10,8] and the pain of numbers that can be used for E and f is [6,4].

<h3>What are the 3 sides of a triangle?</h3>

The hypotenuse of a right triangle is its longest side; its "opposite" side is the one that faces the angle in question; and its "adjacent" side is the one that faces it. We use special terminology to define the sides of right triangles.

We use special terminology to define the sides of right triangles.

The side opposite the right angle is always the hypotenuse of a right triangle. It is the longest side in a right triangle.

The opposing and neighboring sides are the other two sides. The labels on these sides relate to an angle.

One side is across from another at a particular angle.

To learn more about sides of a triangle visit:

brainly.com/question/9449776

#SPJ4

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Degger [83]

Answer:

x = 18.7

Step-by-step explanation:

Gerald's answer is almost correct.  

He just needs to switch the 14 and the x.

it should be

24/x = 18/14

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5 0
3 years ago
The bases of the trapezoid are 6 and 10. The height is 4. Find the area.
kari74 [83]
<h2>Answer:</h2>

b. \ \boxed{32 \sq. \ units}

<h2>Step-by-step explanation:</h2>

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, b_{1}\,and\,b_{2}. Also, the height H of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of b_{1},b_{2}\:and\:H is:

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Since:

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The area is:

A=\frac{(6\text{+}10)4}{2}=\boxed{32 \sq. \ units}

6 0
4 years ago
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4 years ago
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julsineya [31]
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