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denis23 [38]
4 years ago
13

Which factor impacts the possible number of ways in which different atoms can be put together?

Chemistry
1 answer:
irina1246 [14]4 years ago
8 0
<span>An atom's inability to react with all elements in the same way" is the only factor from the given list which impacts the possible number of ways in which different atoms can be put together, since atoms of any given element may or may not react with atoms of another element, depending on various factors ...</span>
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Help Please?<br><br>How many atoms of O are in 2CH4O?<br>How many atoms of H are in 2CH4O?
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Answer:

In 2 molecules of CH4O, we have 2 Oxygens.

In 2 molecules of 2CH4O we have 8 Hydrogens.

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3 years ago
Is neutralizing a base, physical or chemical property?
DIA [1.3K]
Physical property

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8 0
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Describe 2 ways of salting out proteins ​
liubo4ka [24]

The phenomenon known as "salting-out" occurs at very high ionic strengths, when protein solubility declines as ionic strength rises. As a result, salting out may be used to segregate proteins according to how soluble they are in salt solutions.

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8 0
2 years ago
(a)Determine the number of KNO3 molecules in 0.750 mol KNO3.
svp [43]

A. The number of molecules in 0.750 mole of KNO₃ is 4.515×10²³ molecules

B. The mass (in milligrams) of 2.39×10²⁰ molecules of Ag₂SO₄ is 124 mg

C. The number of molecules in 3.429 g of NaHCO₂ is 3.04×10²² molecules

<h3>Avogadro's hypothesis </h3>

1 mole of substance = 6.02×10²³ molecules

<h3>A. How to determine the number of molecules </h3>

1 mole of KNO₃ = 6.02×10²³ molecules

Therefore,

0.750 mole of KNO₃ = 0.75 × 6.02×10²³

0.750 mole of KNO₃ = 4.515×10²³ molecules

<h3>B. How to determine the mass of Ag₂SO₄</h3>

6.02×10²³ molecules = 312 g of Ag₂SO₄

Therefore,

2.39×10²⁰ molecules = (2.39×10²⁰ × 312) / 6.02×10²³

2.39×10²⁰ molecules = 0.124 g

Multiply by 1000 to express in mg

2.39×10²⁰ molecules = 0.124 g × 1000

2.39×10²⁰ molecules = 124 mg of Ag₂SO₄

<h3>C. How to determine the number of molecules </h3>

68 g of NaHCO₂ = 6.02×10²³ molecules

Therefore,

3.429 g of NaHCO₂ = (3.429 × 6.02×10²³) / 68

3.429 g of NaHCO₂ = 3.04×10²² molecules

Learn more about Avogadro's number:

brainly.com/question/26141731

5 0
2 years ago
copper (1) oxide Cu2O is reduced to metallic copper by heating in a stream of hydrogen gas. what mass of water is produced when
dusya [7]
Answer:
             1.41 g of H₂O

Solution:
The equation for given reaction is as follow,

                              Cu₂O  +  H₂     →     2 Cu  +  H₂O

According to equation,

      127 g (2 mole) Cu is produced along with  =  18 g (1 mole) of H₂O
So,
                      10 g Cu produced will generate  =  X g of H₂O

Solving for X,
                     X  =  (18 g × 10 g) ÷ 127 g

                     X  =  1.41 g of H₂O
4 0
3 years ago
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