The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Use substitution.
anywhere you see "a" , than you would plug in b + 2 in for it so....
(b - (b + 2)^4
now take the negative sign and distribute it "+"
so b - b is 0, than 0 - (-2) is -2.
so what is (-2)^4 ????? it would become positive 16
Answer:
a=3
Step-by-step explanation:
If we write y=f(x)=(x-h)²+k, then y-k=(x-h)². This is vertex form where the vertex is (h,k)=(3,3) so h and k are both 3. We can see this if we put x=3 in the shifted function. This is a minimum point for the function because for every other x f(x) is greater then 3. The minimum point is the vertex.
Answer:
104m, 0.096km, 2100cm
Step-by-step explanation:
0.096 kilometres = 9600
2100 cm
104m = 10400 cm
10400, 9600, 2100
104m, 0.096km, 2100cm
Answered by Gauthmath