You must assume that the mass of the rocket and engine remains constant - even though the engine is burning.
You know the engine produces 13.8N for a distance of 14.6m
The total energy expended (work done) by the engine is FxD so you can calculate that
Now - some of that is given to the rocket as kinetic and potential energy, and some is expended against the drag force.
At the peak of its flight ALL the energy given to the rocket is potential energy (its velocity is zero) and that is calculated as mgh
So
Energy given to rocket = mgh
Energy expended by engine = F x D (D= height where engine stops)
Energy 'lost' to drag is the difference between the two values.
Answer:
(C) HBr is an acid .......
Identify key terms : Hand-eye Coordination, physically activity, sportsmanship.
1. The author is informing people about the benefits of regular exercising.
2.Good sportsmanship gives advantages
3.Social Interaction can boost your mood.
4.Quick reactions help you defeat opponents.
5.Sports may be competitive but they teach you valuable life lessons.
In the above problem, we need to find mass of the second child, so that the Center of Mass remains at the origin( pivot).
CM= m1r1+m2r2/m1+m2
0= 20*-2+16*r2/20+16
r2= 40/16
r2= +2.5 m
The time of motion of the object at the given speed and distance is 4 seconds.
<h3>Time of motion of the object</h3>
The time of motion of the object is calculated as follows;
t = d/v
where;
- d is distance = 10 m
- v is speed = 2.5 m/s
- t is time of motion
t = 10/2.5
t = 4 s
Thus, the time of motion of the object at the given speed and distance is 4 seconds.
Learn more about time here: brainly.com/question/2854969
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