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frozen [14]
3 years ago
5

A 50.0-kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. The unstretched length of the

cord is 13.0 m. The jumper reaches reaches the bottom of her motion 40.0 m below the bridge before bouncing back. We wish to find the time interval between her leaving the bridge and her arriving at the bottom of her motion. Her overall motion can be separated into an 13.0-m free-fall and a 27.0-m section of simple harmonic oscillation.] (a) For the free-fall part, what is the appropriate analysis model to describe her motion.
particle under constant acceleration particle in simple harmonic motion particle under constant angular acceleration
Physics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

The the analysis for the free fall part should be done under the constant acceleration.

Explanation:

In the given problem, the jumper is falling under the free fall. Since, no external force is acting on the body therefore, the fall will be under the action gravity only. also, the acceleration due to gravity is always constant.

Therefore, the the analysis for the free fall part should be done under the constant acceleration.

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Part complete Sound with frequency 1240 Hz leaves a room through a doorway with a width of 1.11 m . At what minimum angle relati
Sedbober [7]

Answer:

14.43° or 0.25184 rad

Explanation:

v = Speed of sound in air = 343 m/s

f = Frequency = 1240 Hz

d = Width in doorway = 1.11 m

Wavelength is given by

\lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{343}{1240}\\\Rightarrow \lambda=0.2766\ m

In the case of Fraunhofer diffraction we have the relation

dsin\theta=\lambda\\\Rightarrow \theta=sin^{-1}\frac{\lambda}{d}\\\Rightarrow \theta=sin^{-1}\frac{0.2766}{1.11}\\\Rightarrow \theta=14.43^{\circ}\ or\ 0.25184\ rad

The minimum angle relative to the center line perpendicular to the doorway will someone outside the room hear no sound is 14.43° or 0.25184 rad

6 0
3 years ago
A tub of water is placed in a small room and heat is removed from the room. What will most likely occur if enough heat is remove
NARA [144]

Answer:

(A)The water will freeze.

Explanation:

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In this case if enough heat is removed from the room the internal movement of the water particles will slow down causing the water to form crystal lattice thus forming ice. So, the water will freeze.

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3 years ago
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3 years ago
In reaching her destination, a backpacker walks with an average velocity of 1.41 m/s, due west. This average velocity results, b
V125BC [204]
The total average velocity v=+1.41 m/s (I assume west as positive direction) is given by the total displacement, S, divided by the total time taken, t:
v= \frac{S}{t}= \frac{S_1+S_2}{t_1+t_2}
where:
-The total displacement S is the algebraic sum of the displacement in the first part of the motion (S_1=6.30 km=6300 m, due west) and of the displacement in the second part of the motion (S_2, due east).
-The total time taken t is the time taken for the first part of the motion, t_1, and the time taken for the second part of the motion, t_2. t_1 can be found by using the average velocity and the displacement of the first part:
t_1= \frac{S_1}{v_1}= \frac{6300 m}{2.49 m/s}=2530 s

t_2, instead, can be written as \frac{S_2}{v_2}, where v_2=-0.630 m/s is the average velocity of the second part of the motion (with a negative sign, since it is due east). 

Therefore, we can rewrite the initial equation as:
v=1.41 = \frac{6300+S_2}{2530- \frac{S_2}{0.630} }
And by solving it, we find the displacement in the second part of the motion (i.e. how far did the backpacker move east):
S_2=-844 m=-0.844 km

4 0
3 years ago
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