This 80 kg car is moving at 20m/sec at the top where the hills radius is 100m. What is the centrifugal force?

Look at the advertisement. A poster that reads, "There's more to resistors than resistance. If you're really serious about cost,

ozzi

Options:

universal appeal

flattery

association

bandwagon

Answer: Association

Explanation: Advertisement is a marketing technique through which business organisations utilize the opportunities provided by both the print, electronic and other channels of communication to market a product to the target audience.

Association Advertising is a type of Advertising where certain attributes which have been known to be associated with good and quality products are used to market the products to the target audience.

7 0

3 years ago

Read 2 more answers

Pls help me quickly ......

marishachu [46]

Answer:

the last one: weight force

3 0

2 years ago

Two rocks of different masses are rolling down a hill at the same speed. Which rock (small one or big one) would have more kinet

aivan3 [116]

Answer:

Kinetic energy of bigger rock will be more than that of smaller one.

Explanation:

Kinetic energy of the rock is given by,

Kinetic energy = $\frac{1}{2} m v^{2}$

As velocity of both the rocks are same. Thus, kinetic energy is directly proportional to the mass of the rock

Kinetic energy ∝ mass

So, For greater mass kinetic energy will be greater and for smaller mass kinetic energy will be smaller.

Hence, Kinetic energy of bigger rock will be more than that of smaller one.

3 0

2 years ago

Read 2 more answers

N a laboratory test of tolerance for high acceleration, a pilot is swung in a circle 11.5 m in diameter. it is found that the pi

Deffense [45]

<span>59.027m/s^2 Centripetal force is give by F = mv^2/r Since F = ma The acceleation accoiated with this centripetal force is a=v^2/r the radius is found by r=d/2=5.75m velocity is found by v=d/t distance is the circumference of the circle c=pi*d=11.5*3.14=36.11m time=60s/30.6rpm=1.96s v=36.11/1.96=18.423m/s plugging this back in to a=v^2/r=(18.423m/s)^2/5.75m=59.027m/s^2</span>

8 0

3 years ago

A playground merry-go-round has radius 2.10m and moment of inertia 2500kg*m^2 about a vertical axle through its center, and it t

vladimir2022 [97]

Answer

Radius of the wheel r = 2.1 m

Moment of inertia I = 2500 Kg m²

Tangential force applied F = 18 N

Time interval t = 16 s

Initial angular speed ω1 = 0

Final angular speed ω2 = ?

Let α be the angular acceleration.

Torque applied τ = Iα

F r = Iα

Angular acceleration α = F r/I

= $\dfrac{18\times 2.1}{2500}$

= 0.015 rad/s²

(a)From rotational kinematic relation

Final angular speed ω₂ = ω₁ + αt

= 0 + (0.015 rad/s^2 * 16 s)

= 0.24 rad/s

(b) Work done W = 0.5 Iω₂² - (1/2)Iω₁²

= 0.5*( 2500 Kg m²)(0.24 rad/s)^2 - 0

= 72 J

(c) Average power supplied by the child P = W/t = $\dfrac{72}{16}$

= 4.5 watt

8 0

2 years ago