A radio frequency identification application would most likely interface with an Operational Data Store.
The Operations Data Store (ODS) is a central database that provides the latest data snapshots from multiple transaction systems for operational reporting.
It allows organizations to combine data in its original format from various sources into a single destination to provide business reporting.
ODS contains integrated updates from operational sources and supports business intelligence (BI) tools to facilitate tactical decision making.
For example, an administrator can configure ODS to pull weekly batches of data from a billing application that is rarely updated, importing individual transaction records as they occur in the sales database(thanks to these database triggers), then combine the two into new relational tables.
As a result, querying and reporting on operational data in ODS comes with the assurance that these integrated tables contain the latest and most relevant snapshots of the business.
Learn more about Operations Data Store here : brainly.com/question/14925154
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You have effectively got two capacitors in parallel. The effective capacitance is just the sum of the two.
Cequiv = ε₀A/d₁ + ε₀A/d₂ Take these over a common denominator (d₁d₂)
Cequiv = ε₀d₂A + ε₀d₁A / (d₁d₂) Cequiv = ε₀A( (d₁ + d₂) / (d₁d₂) )
B) It's tempting to just wave your arms and say that when d₁ or d₂ tends to zero C -> ∞, so the minimum will occur in the middle, where d₁ = d₂
But I suppose we ought to kick that idea around a bit.
(d₁ + d₂) is effectively a constant. It's the distance between the two outer plates. Call it D.
C = ε₀AD / d₁d₂ We can also say: d₂ = D - d₁ C = ε₀AD / d₁(D - d₁) C = ε₀AD / d₁D - d₁²
Differentiate with respect to d₁
dC/dd₁ = -ε₀AD(D - 2d₁) / (d₁D - d₁²)² {d2C/dd₁² is positive so it will give us a minimum} For max or min equate to zero.
-ε₀AD(D - 2d₁) / (d₁D - d₁²)² = 0 -ε₀AD(D - 2d₁) = 0 ε₀, A, and D are all non-zero, so (D - 2d₁) = 0 d₁ = ½D
In other words when the middle plate is halfway between the two outer plates, (quelle surprise) so that
d₁ = d₂ = ½D so
Cmin = ε₀AD / (½D)² Cmin = 4ε₀A / D Cmin = 4ε₀A / (d₁ + d₂)
Explanation:
it holds protons and neutrons together
Answer:
The velocity is 
The pressure is 
Explanation:
From the question we are told that
The speed at which water is travelling through is 
The pressure is 
The diameter of the new pipe is 
Where D is the diameter of first pipe
According to the principal of continuity we have that
Now 
is the area of the first pipe which is mathematically represented as
and 
is the area of the second pipe which is mathematically represented as
Recall
![A_2 = \pi \frac{[ D^2]}{4 *4}](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cpi%20%20%5Cfrac%7B%5B%20D%5E2%5D%7D%7B4%20%2A4%7D)
So 
substituting value
According to Bernoulli's equation we have that
substituting values
