If there is a current of 15A in a circuit for 5 minutes, what quantity of electric charge flow through the circuit?

A sample of an unknown volatile liquid was injected into a Dumas flask (mflask = 27.0928 g, Vflask = 0.1040 L) and heated until

NNADVOKAT [17]

Answer:

The gas was Hexane

Explanation:

taking the diference between the mass of the flask and the final mass qe can calculate the mass of liquid injected (assuming none escaped the flask):

$m_{l} = 27.4593g - 27.0928g = 0.3665g$

with the volume of the flask we can get the density of the gas at the indicated pressure and temperature:

$d_{g} = \frac{0.3665 g}{0.1040L} = 3.524 g/L$

From the ideal gases law we have that the density can be calculated as:

$d_{g} = \frac{P*M}{R*T}$

Where R is the ideal gases constant = , and M the molecular weight of the fluid. Solving for M:

$M=\frac{d_{g}*R*T}{P}=\frac{3.524g/L*0,082atmL/molK*291K}{0.976atm}$

$M=86.16 g/mol$

Note that the temperature is computed in Kelvin T= 18+273=291K

The gas with the closer molar mass is Hexane

4 0

3 years ago

39.Explain the working mechanism of a mercury barometer.

alina1380 [7]

One end is sealed to prevent air from disturbing the scale and measures. Therefore, a Mercury Barometer works on the principle of balancing the atmospheric pressure with the volume of mercury present in the device

7 0

3 years ago

A cue ball initially moving at 3.4 m/s strikes a stationary eight ball of the same size and mass. After the collision, the cue b

romanna [79]

Answer:

speed of eight ball speed after the collision is 3.27 m/s

Explanation:

given data

initially moving v1i = 3.4 m/s

final speed is v1f = 0.94 m/s

angle = θ w.r.t. original line of motion

solution

we assume elastic collision

so here using conservation of energy

initial kinetic energy = final kinetic energy .............1

before collision kinetic energy = 0.5 × m× (v1i)²

and

after collision kinetic energy = 0.5 × m× (v1f)² + 0.5 × m× (v2f)²

put in equation 1

0.5 × m× (v1i)² = 0.5 × m× (v1f)² + 0.5 × m× (v2f)²

(v2f)² = (v1i)² - (v1f)²

(v2f)² = 3.4² - 0.94²

(v2f)² = 10.68

taking the square root both

v2f = 3.27 m/s

speed of eight ball speed after the collision is 3.27 m/s

5 0

3 years ago

Why does the position of the ocean ellipse change over the course of a given week?

alekssr [168]

Since the ocean is made of something called WATER, and water flows... the ocean will flow! :D

5 0

3 years ago

Read 2 more answers

Hooke's law describes an ideal spring. Many real springs are better described by the restoring force (F Sp ) s =−kΔs−q(Δs) 3 (p)

Montano1993 [528]

Answer with Explanation:

We are given that

Restoring force, $(FS_p)s=-k\Delta s-q(\Delta s)^3$

$k=350N/m$

$q=750 N/m^3$

We have to find the work must you do to compress this spring 15 cm.

$\Delta s=15 cm=0.15 m$

Using 1 m=100 cm

Work done= $\int_{0}^{0.15}-Fd(\Delta s)$

W= $-\int_{0}^{0.15}(-k\Delta s-q(\Delta s)^3))d(\Delta s)$

$W=k[\frac{(\Delta s)^2}{2}]^{0.15}_{0}+q[\frac{(\Delta s)^4}{4}]^{0.15}_{0}$

$W=0.01125k+0.000127q=0.01125\times 350+0.000127\times 750$

$W=4.033 J$

Ideal spring work= $0.5k(\Delta s)^2=0.5\times 350\times (0.15)^2=3.938 J$

Percentage increase in work= $\frac{4.033-3.938}{3.928}\times 100=2.4$ %

6 0

4 years ago