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Dafna1 [17]
4 years ago
8

What is the first quartile of the set of data shown below?

Mathematics
1 answer:
MatroZZZ [7]4 years ago
3 0
The answer is B because it is the middle of 16 and 24
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Question of the Day<br><br> Find B
zheka24 [161]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
The quotient of
vova2212 [387]
\displaystyle{  \frac{y^2-16}{4y-16} \div \frac{y+4}{16y}= \frac{y^2-16}{4y-16}\cdot\frac{16y}{y+4}\\\\

\displaystyle{ = \frac{y^2-4^2}{4(y-4)} \cdot\frac{16y}{y+4}= \frac{(y-4)(y+4)}{4(y-4)}\cdot\frac{16y}{y+4} = \frac{16y}{4}=4y


Answer: 4y 


Remark: y^2-4^2=(y-4)(y+4) by the difference of squares identity, or formula.
6 0
3 years ago
Create a number line to illustrate the following operations and find the solution.
Alika [10]

Answer:

create a number line to illustrate the following operations and find the solution.

6 0
3 years ago
Can someone help! with this please.
Brut [27]
The two equations are

y=7x+5
y=4x+25

the only time the bags would match prices would be a bag that weighs 6.667 pounds and it would be worth $51.67
3 0
3 years ago
Please help me with the first question
tatuchka [14]
I assume the carpet has the shape of a rectangle.

Let L = length
Let W = width

The area is 192 ft^2.
LW = 192
The perimeter is 56 ft.
2L + 2W = 56

We have a system of 2 equation in 2 unknowns.
LW = 1922L + 2W = 56
Divide the second equation by 2:
L + W = 28
Subtract W from both sides.

L = 28 - W

Substitute 28 - W for L in the first equation.

LW = 192
(28 - W)W = 192
28W - W^2 = 192

W^2 - 28W + 192 = 0
(W - 12)(W - 16) = 0
W - 12 = 0  or  W - 16 = 0
W = 12 or W = 16

L = 28 - W

For W = 12: L = 28 - 12 = 16
For W = 16" L = 28 - 16 = 12

We get: length = 16 and width = 12
or: length = 12 and width = 16
Either answer is correct, but since people think the length is longer than the width, answer with a longer length than the width.
Answer: Length = 16 ft   Width = 12 ft

5 0
3 years ago
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