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Anettt [7]
3 years ago
10

Find the cosine and sine of 210. Round your answers to the nearest hundredth if necessary

Mathematics
2 answers:
Assoli18 [71]3 years ago
8 0
The cosine is -0.88
This is rounded from <span>-0.88387747318

The sine is .48.
This is rounded from </span><span>0.46771851834</span>
Digiron [165]3 years ago
8 0

Answer:

sin 210^{\circ}=-0.5

cos 210^{\circ}=-0.87

Step-by-step explanation:

We are given that

sin210^{\circ} and cosin 210^{\circ}

We have to find the value of cosine and sine 210 degrees.

sin 210^{\circ}= sin (\pi+30)= - sin 30^{\circ}   (\pi=180^{\circ}, sin(\pi+\theta)=-sin\theta)

sin 210^{\circ}=-\frac{1}{2}=-0.5   ..... (sin 30^{\circ}=\frac{1}{2})

cos 210^{\circ}=cos (\pi+30)

cos 210^{\circ}=-cos 30^{\circ}=-\frac{\sqrt3}{2}

cos 210^{\circ}=-0.87

 cos (\pi+\theta)=-cos\theta, cos30^{\circ}=\frac{\sqrt3}{2})

Hence, the value of

sin 210^{\circ}=-0.5

cos 210^{\circ}=-0.87

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Answer:

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Step-by-step explanation:

Hi there!

We know that BC has a midpoint M, with the coordinates (6,6), and the endpoint C, with coordinates (2, 10)

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The midpoint formula is (\frac{x_1 + x_2}{2}, \frac{y_1+ y_2}{2}), where (x_1, y_1) and (x_2 , y_2) are points. In this case, the point C has the values of (x_1, y_1), and B has the values of (x_2 , y_2)

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