Is it supposed to be equal to something, maybe "0"? You wouldn't be able to solve this without that.
since we have the area of the front side, to get its volume we can simple get the product of the area and the length, let's firstly change the mixed fractions to improper fractions.
![\stackrel{mixed}{23\frac{2}{3}}\implies \cfrac{23\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{71}{3}} ~\hfill \stackrel{mixed}{4\frac{7}{8}}\implies \cfrac{4\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{39}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{71}{3}\cdot \cfrac{39}{8}\implies \cfrac{71}{8}\cdot \cfrac{39}{3}\implies \cfrac{71}{8}\cdot 13\implies \cfrac{923}{8}\implies 115\frac{3}{8}~in^3](https://tex.z-dn.net/?f=%5Cstackrel%7Bmixed%7D%7B23%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B23%5Ccdot%203%2B2%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B71%7D%7B3%7D%7D%20~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B4%5Cfrac%7B7%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%208%2B7%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B39%7D%7B8%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B71%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B39%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B71%7D%7B8%7D%5Ccdot%20%5Ccfrac%7B39%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B71%7D%7B8%7D%5Ccdot%2013%5Cimplies%20%5Ccfrac%7B923%7D%7B8%7D%5Cimplies%20115%5Cfrac%7B3%7D%7B8%7D~in%5E3)
Answer:
I'm going to assume that you meant y=3x-8 and y=-4
This means that you would substitute -4 into the spot of y which gives you -4=3x-8. Once solved you would receive x=4/3.
Hope I helped have a nice day :)
You could pick just about anything 3/8 is not the same thing as 5/7 and neither is 3/4
Something that is equivalent would be something like 10/14 or 20/28