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docker41 [41]
4 years ago
9

2.9 A young engineer is asked to design a thermal protec- tion barrier for a sensitive electronic device that might be exposed t

o irradiation from a high-powered infrared laser. Having learned as a student that a low thermal conductivity material provides good insulating charac- teristics, the engineer specifies use of a nanostructured aerogel, characterized by a thermal conductivity of ka % 0.005 W/m! K, for the protective barrier. The engi- neer’s boss questions the wisdom of selecting the aero- gel because it has a low thermal conductivity. Consider the sudden laser irradiation of (a) pure aluminum, (b) glass, and (c) aerogel. The laser provides irradiation of G % 10 + 106 W/m2 . The absorptivities of the materials are ' % 0.2, 0.9, and 0.8 for the aluminum, glass, and aerogel, respectively, and the initial temperature of the barrier is Ti % 300 K. Explain why the boss is concerned. Hint: All materials experience thermal expansion (or contraction), and local stresses that develop within a material are, to a first approximation, proportional to the local temperature gradient.

Engineering
1 answer:
morpeh [17]4 years ago
8 0

Answer:

attached

Explanation:

From Table A-1 for pure aluminum at 300 K

k_al = 238 Wm • K

From Table A-3 for pure glass at 300 K

k_gl = 1.4 Wm•K

Applying the energy balance.  

q_s'' =   q_abs''

Hence,  

formula is attached find the first attachment

Substituting for all cases we get  

formula is attached find the second attachment

So that, using the aerogel material as an insulation will be accompanied by high therms stresses in the protection layer which results in a rapid damage for this layer and thus the device will face the thermal hazard.  

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Discuss with your neighbor your brain as a computer.
Misha Larkins [42]
Senors are a type of device that produce a amount of change to the output to a known input stimulus.
Input signals are signals that receive data by the system and outputs the ones who are sent from it. Hope this helps ;)
6 0
4 years ago
To convert from the U.S. Customary (FPS) system of units to the SI system of units. A first-year engineering student records thr
LenaWriter [7]

This question is incomplete, the complete question is;

To convert from the U.S. Customary (FPS) system of units to the SI system of units. A first-year engineering student records three separate measurements as 653 lb, 69.0 mi/h, and 293 × 10⁶ ft². Suppose this engineering student has to turn in the results, but the professor only accepts results given in SI units.  

Required:

What is the area measurement, 293 × 10⁶ ft², in SI units?

293 × 10⁶ ft² = ?km²

Answer:

the area measurement is  27.221 km²

Explanation:

Given the data in the question;

What is the area measurement, 293 × 10⁶ ft², in SI units

we are to the result of the measured area from ft² to km²

we know that;

1 meter = 3.2808 ft

1 km = 1000 m

1 ft = (1 / 3.2808)m

1 m = ( 1/1000 ) km

since our measured are is 293 × 10⁶ ft²

hence

A = 293 × 10⁶ × [ (1 / 3.2808)m ]²

A = 27221252.74 m²

A = 27221252.74 × [ ( 1/1000 ) km ]²

A = 27.221 km²

Therefore, the area measurement is  27.221 km²

7 0
3 years ago
Explain the advantages of continuous insulation in envelope assemblies and why it is better to have the continuous insulation on
Luden [163]

Answer:

Continuous insulation helps in eliminating the  necessity of applying extra materials to achieve moisture barrier demands, reducing labor and material cost.

Continuous insulation helps building last much longer over a period of time,without the need to upgrade and repair.

Inside the placement of continuous insulation in the envelope needed includes the following; the foundation wall or slab insulation, balcony interface, bond joist insulation, insulation against sub floor, on the interior of masonry wall.

Explanation:

Solution:

The analytical path to success contains a well planned and designed building exterior, which avoids the loss of energy, control cost and the maximization of technology advancement in materials.

Property installed continuous insulation on the exterior can also execute as an air barrier. the flashing of wall penetrations can form into a drainage plane. this plane can stop potentially damaging moisture from entering into the wall assembly.

By making use of continuous insulation it helps in removing necessity of applying extra materials to achieve moisture barrier demands, reducing labor and material cost.

Continuous insulation helps building to withstand the test of time without the need to upgrade and repair

Now inside the placement of continuous insulation in the envelope is needed as follows:

  • Foundation wall or slab insulation
  • Insulation against sub floor
  • Balcony interfaces
  • On the interior of masonry wall
  • Bond  joist insulation
6 0
4 years ago
The enthalpy of the water entering an actual pump is 500 kJ/kg and the enthalpy of the water leaving it is 550 kJ/kg. The pump h
n200080 [17]

Answer:500,551.02

Explanation:

Given

Initial enthaly of pump \left ( h_1\right )=500KJ/kg

Final  enthaly of pump \left ( h_2\right )=550KJ/kg

Final  enthaly of pump when efficiency is 100%=h_2^{'}

Now pump efficiency is 98%

\eta=\frac{h_2-h_1}{h_2^{'}-h_1}

0.98=\frac{550-500}{h_2-500}

h_2=551.02KJ/kg

therefore initial and final enthalpy of pump for 100 % efficiency

initial=500KJ/kg

Final=551.02KJ/kg

3 0
3 years ago
A three-point bending test was performed on an aluminum oxide specimen having a circular cross section of radius 5.0 mm (0.20 in
Sonja [21]

The load is 17156 N.

<u>Explanation:</u>

First compute the flexural strength from:  

σ = FL / πR^{3}

   = 3000 \times (40 \times 10^-3) / π (5 \times 10^-3)^3

σ = 305 \times 10^6 N / m^2.

We can now determine the load using:

F = 2σd^3 / 3L

  = 2(305 \times 10^6) (15 \times 10^-3)^3 / 3(40 \times 10^-3)

F = 17156 N.  

7 0
4 years ago
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