Nec Article 430 covers selection of time-delay fuses for motor- overload protection.
<h3>What article in the NEC covers motor overloads?</h3>
Article 430 that is found in National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .
Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.
Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.
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The Bidirectional Shift Register is the shift register that allows one to write a 5bit register if the series is shifted from left to right.
<h3>What is a value of a 5-bit register?</h3>
A 5-bit register is valuable because it can represent up to 32 items. It is to be noted that a bit is a digit that is binary that is indicative of two states.
While a 5-bit register can have a possible number of 32 values,
- 6 can hold 64;
- 7 can hold 128;
- 8 can hold 256 etc.
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Answer:
r=0.31
Ф=18.03°
Explanation:
Given that
Diameter of bar before cutting = 75 mm
Diameter of bar after cutting = 73 mm
Mean diameter of bar d= (75+73)/2=74 mm
Mean length of uncut chip = πd
Mean length of uncut chip = π x 74 =232.45 mm
So cutting ratio r


r=0.31
So the cutting ratio is 0.31.
As we know that shear angle given as

Now by putting the values

\
Ф=18.03°
So the shear angle is 18.03°.
Answer:
The couples are not all on one axis or plane for that matter but if the A and B connector had to be specified it would go by the yz axis diagonal to the x axis with a magnitude of about 15. The direction of the axis would be pointed up to the second quadrant. Hope this was helpful
Explanation:
Answer:
critical clearing angle = 70.3°
Explanation:
Generator operating at = 50 Hz
power delivered = 1 pu
power transferable when there is a fault = 0.5 pu
power transferable before there is a fault = 2.0 pu
power transferable after fault clearance = 1.5 pu
using equal area criterion to determine the critical clearing angle
Attached is the power angle curve diagram and the remaining part of the solution.
The power angle curve is given as
= Pmax sinβ
therefore : 2sinβo = Pm
2sinβo = 1
sinβo = 0.5 pu
βo =
⁰
also ; 1.5sinβ1 = 1
sinβ1 = 1/1.5
β1 =
= 41.81⁰
∴ βmax = 180 - 41.81 = 138.19⁰
attached is the remaining solution
The critical clearing angle =
≈ 70.3⁰