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Vikki [24]
3 years ago
12

In a study comparing banks in Germany and Great Britain, a sample of 145 matched pairs of banks was formed. Each pair contained

one bank from Germany and one from Great Britain. The pairings were made in such a way that the two members were as similar as possible in regards for factors like size and age. The ratio of total loans outstanding to total assets was calculated for each bank. For this ration, the sample mean difference (German – Great Britain) was 0.0518 and the sample standard deviation of the differences was 0.3055. Test, against a two sided alternative, the null hypothesis that the two population means are equal.
Engineering
1 answer:
elena55 [62]3 years ago
5 0

Answer:

The difference between the two population is mean

Explanation:

Let the population mean for Germany and Great Britain be represented by \mu_1 and \mu_2 respectively hence

Null hypothesis

H_o: \mu_1-\mu_2=0

Alternative hypothesis

H_1: \mu_1-\mu_2\neq 0

Taking \alpha=0.05  

s_d=0.3055

\bar d=\bar x-\bar y=0.0518

Sample size, n=145

Student’s t statistics is given by

t=\frac {\bar d \sqrt n}{s_d}=\frac {0.0518\times \sqrt 145}{0.3055}=2.042

From t table, t_{n-1,\alpha/2}=t_{144,0.025}=1.977

The decision rule is to reject null hypothesis if

\frac {\bar d \sqrt n}{s_d}>t_{n-1, \alpha/2}

Therefore, we reject the null hypothesis because the computed t value is more than critical value. We conclude that the difference between the two population is mean.

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Answer:

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Explanation:

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6 0
3 years ago
technician a says that the higher the gear selected the more torque is available. technician b says that a transaxle contains ge
umka21 [38]

Technician A is correct. Technician B is wrong because a gear's transmission is used to increase or decrease torque.

The relation torque is relying on multiplying the circumferential detail with the resource of the usage of the radius; massive gears experience a greater amount of torque, at the same time as smaller gears experience a great deal much less torque. Similarly, the torque ratio is equal to the ratio of the gears' radii. A gear's transmission torque modifications as it will boom or decreases speed. Commonly, with the resource of the usage of lowering the speed, a small torque on the doorway issue is transferred as a massive torque at the output issue. The calculation of torque is quantified with the resource of the usage of an extensive form of teeth.

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3 0
1 year ago
Consider the expansion of a gas at a constant temperature in a water-cooled piston-cylinder system. The constant temperature is
Leona [35]

Answer:

Q_{in} = W_{out} = nRT ln (\frac{V_{2}}{V_{1}})

Explanation:

According to the first thermodynamic law, the energy must be conserved so:

dQ = dU - dW

Where Q is the heat transmitted to the system, U is the internal energy and W is the work done by the system.

This equation can be solved by integration between an initial and a final state:

(1) \int\limits^1_2 {} \, dQ = \int\limits^1_2 {} \, dU - \int\limits^1_2 {} \, dW

As per work definition:

dW = F*dr

For pressure the force F equials the pressure multiplied by the area of the piston, and considering dx as the displacement:

dW = PA*dx

Here A*dx equals the differential volume of the piston, and considering that any increment in volume is a work done by the system, the sign is negative, so:

dW = - P*dV

So the third integral in equation (1) is:

\int\limits^1_2 {- P} \, dV

Considering the gas as ideal, the pressure can be calculated as P = \frac{n*R*T}{V}, so:

\int\limits^1_2 {- P} \, dV = \int\limits^1_2 {- \frac{n*R*T}{V}} \, dV

In this particular case as the systems is closed and the temperature constant, n, R and T are constants:

\int\limits^1_2 {- \frac{n*R*T}{V}} \, dV = -nRT \int\limits^1_2 {\frac{1}{V}} \, dV

Replacion this and solving equation (1) between state 1 and 2:

\int\limits^1_2 {} \, dQ = \int\limits^1_2 {} \, dU + nRT \int\limits^1_2 {\frac{1}{V}} \, dV

Q_{2} - Q_{1} = U_{2} - U_{1} + nRT(ln V_{2} - ln V_{1})

Q_{2} - Q_{1} = U_{2} - U_{1} + nRT ln \frac{V_{2}}{V_{1}}

The internal energy depends only on the temperature of the gas, so there is no internal energy change U_{2} - U_{1} = 0, so the heat exchanged to the system equals the work done by the system:

Q_{in} = W_{out} = nRT ln (\frac{V_{2}}{V_{1}})

4 0
3 years ago
A program is seeded with 30 faults. During testing, 21 faults are detected, 15 of which are seeded faults and 6 of which are ind
Vesna [10]

Answer:

Estimated number of indigenous faults remaining undetected is 6

Explanation:

The maximum likelihood estimate of indigenous faults is given by,

N_F=n_F\times \frac{N_S}{n_S} here,

n_F = the number of unseeded faults = 6

N_S = number of seeded faults = 30

n_s = number of seeded faults found = 15

So NF will be calculated as,

N_F=6\times \frac{30}{15}=12

And the estimate of faults remaining is  N_F-n_F = 12 - 6 = 6

8 0
2 years ago
For welding the most important reason to use jigs and fixtures in a welding shop is to
diamong [38]

Answer:

Reduce manufacturing costs.

Explanation:

Hope This Helps

Have A Great Day

7 0
2 years ago
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