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Marat540 [252]
3 years ago
10

Explain which of the following are correct statements of the Second Law of Thermodynamics and which are not. a. All reversible h

eat engines have the same efficiency. b. An engine connected to one heat reservoir can do work on the surroundings. c. An engine connected to two heat reservoirs at different temperatures can do work on the surroundings. d. The entropy of the universe is conserved.
Chemistry
1 answer:
Ivan3 years ago
3 0

Answer:

a. False

b. False

c. True

d. False

Explanation:

The Second Law of Thermodynamics (2LT) has two principal states, one about the heat engines, and other about the entropy.

Heat engines are machines that work by converting heat at work. According to the 2LT, a machine like that can't convert all of the heat in work, some of it must be lost by the surroundings.

Thus, those machines, which is cyclic, can't have an efficiency of 100%, but, depending on the temperature, and the fluid used, it will vary, so, the letter "a" is false.

The engine must be connected to a hot heat reservoir, which will be a high temperature and will warm up the fluid, and to a cold heat reservoir, which will a low temperature and will be the deposit of the heat loss. So, the letter "b" is incorrect, and the letter "c" is correct.

According to the other statement of the 2LT, the entropy, a measure of the randomness, intends to increase in all of the systems, including the universe. So, as more unorganized is a system, as large as the entropy. So, the letter "d" is incorrect.

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890J of heat are applied to a piece of aluminum, causing a 4.6°C increase in its temperature. The specific heat of aluminum is 0
Semmy [17]

Answer:

The answer would be C 214g

Explanation:

890j of heat causes 4.6°c increase in temperature

specific heat of aluminium after is o.9022 j /g°c

now by using the formula .The mass of aluminium would be c that is 214 g

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3 years ago
Which of the following elements is the smallest?
Oliga [24]

Answer:

Explanation:

The atomic radius of elements are used to estimate the sizes of elements. The atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.

To solve this problem we will obtain the atomic radius values of the given elements from a standard atomic radius table;

          Si          111 pm

           P          98 pm

          Cl          79 pm

            S           87pm

pm = picometer

We see that chlorine has the least atomic radius

7 0
4 years ago
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Identify which of the following two reactions you would expect to occur more rapidly: (1) addition of HBr to 2-methyl-2-pentene
arlik [135]

Answer:

(1) addition of HBr to 2-methyl-2-pentene

Explanation:

In this case, we will have the formation of a <u>carbocation</u> for each molecule. For molecule 1 we will have a <u>tertiary carbocation</u> and for molecule 2 we will have a <u>secondary carbocation</u>.

Therefore the <u>most stable carbocation</u> is the one produced by the 2-methyl-2-pentene. So, this molecule would react faster than 4-methyl-1-pentene. (See figure)

3 0
3 years ago
Which is the formula for diarsenic pentoxide?
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Formula for diarsenic pentoxide
As2O5
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If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

                            C   +   O₂    -------------> CO₂

                          1 mol    1 mol                  1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

           C               +                        O₂                     ------------->        CO                 1 mol (12 g/mol)                      1 mol (32 g/mol)                      1 mol (44 g/mol)

                   

              C   +   O₂    -------------> CO₂

            12 g       32 g                   44 g

So,

we come to know that 32 g of Oxygen combine with 12 g  of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

                32 g of  O₂ ≅ 12 g of  C

                  11 g of O₂  ≅  g of  C

by doing cross multiplication

           g of C = 12 g x 11 g / 32 g

           g of C = 132 g / 32 g

           g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

                     12 g of  C ≅ 44 g of CO₂

                     4.13 g of C ≅  g of  CO₂

by doing cross multiplication

                    g of  CO₂ = 44 g x 4.13 g / 12 g

                    g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0
3 years ago
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