All categories

3 years ago

How will adding NaCl affect the freezing point of a solution?

Chemistry

2 answers:

lord [1]3 years ago

3 0

Answer is: adding NaCl will lower the freezing point of a solution.

A solution (in this example solution of sodium chloride) freezes at a lower temperature than does the pure solvent (deionized water).

The higher the solute concentration (sodium chloride), freezing point depression of the solution will be greater.

Equation describing the change in freezing point:

ΔT = Kf · b · i.

ΔT - temperature change from pure solvent to solution.

Kf - the molal freezing point depression constant.

b - molality (moles of solute per kilogram of solvent).

i - Van’t Hoff Factor.

Dissociation of sodium chloride in water: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).

valentinak56 [21]3 years ago

3 0

Adding NaCl (salt) will lower the freezing point. Examples of this include salt water bodies like the ocean, and why salt is spread on roadways during snow and icy conditions.

You might be interested in

25g of magnesium chloride (MgCl2) was dissolved in 250 ml distilled water at 25oC. The density of water was 0.9975g/cm3 . Calcul

andriy [413]

Answer:

[MgCl₂] = 1.05 m

Explanation:

Molality is a type of concentration that indicates the moles of solute in 1000g of solvent.

m = mol/kg.

Our solute is MgCl₂. We convert mass to moles:

25 g . 1mol / 95.21 g = 0.262 moles.

Our solvent is water → 250 mL of H₂O

We use density to determine the mass: density = m / V

Density . V = m → 0.9975 g/mL . 250 mL = 249.3 g

We convert from g to kg = 249.3 g . 1kg/1000g = 0.2493kg

molality → 0.262 mol /0.2493kg = 1.05

6 0

2 years ago

What does the presence of tiny crystals in a piece of igneous rock tell you about it?

Ksenya-84 [330]

Answer:

Neron po bang story o wala poh

6 0

2 years ago

Consider the balanced chemical equation that follows. You are asked to determine how many moles of water you can produce from 4.

matrenka [14]

Explanation:

According to law of conservation of mass, mass of the reactants is equal to the mass of products in a chemical equation. As mass can neither be created nor it can be destroyed but it can be transformed from one form to another.

As it is given that hydrogen and in excess oxygen is reacting that leads to the formation of water. Hence, the chemical reaction equation will be as follows.

$2H_{2}(g) + O_{2}(g) \rightarrow 2H_{2}O(l)$

Since, it is given that 4 mol of hydrogen is reacting with excess of oxygen and gives 2 moles of water.

Hence, number of moles of water produced is calculated as follows.

4 mol of $H_{2} \times \frac{2 mol of H_{2}O}{2 mol of H_{2}}$

= 4 moles of $H_{2}O$

Thus, we can conclude that 4 moles of water you can produce from 4.0 mol of hydrogen and excess oxygen.

3 0

3 years ago

A compound is 52.14% C, 13.13% H, and 34.73% O. What is the empirical formula of the compound?

alina1380 [7]

% H = 100 - ( 52.14 + 34.73 )=13.13 %

assume 100 g of this compound 
mass H = 13.13 g 
moles H = 13.13 g / 1.008 g/mol=13 

mass C = 52.14 g 
moles C = 52.14 g/ / 12.011 g/mol=4 

mass O = 34.73 g 
moles O = 34.73 g/ 15.999 g/mol=2 

the empirical formula is C4H13O2

7 0

3 years ago

Read 2 more answers

Using the Hoffman apparatus for electrolysis, a chemist decomposes 2.3 moles of water into its gaseous elements. How many grams

solong [7]

Answer:

2.318032g

Explanation:

-The electrolysis equation of water is written as below:

$2H_2O_{(l)}->2H_2_{(g)}+O_2_{(g)}$