All categories

4 years ago

Water boils at a higher temperature than a non-polar solvent like ether because...

2 answers:

7 0

E a large amount of energy is required to break the many hydrogen bonds that restrict the movement of individual water molecules.

Katena32 [7]4 years ago

5 0

Water boils at a higher temperature that a non-polar solvent like ether because a large amount of energy is required to break the many hydrogen bonds that restrict the movement of individual water molecules. The answer is E. Hope it helps.

You might be interested in

Which of these formulas is the formula font the base calcium hydroxide

zhenek [66]

Ca(OH)2 is the answer for plato

4 0

4 years ago

The virial equation of state is not recommended to be used for polar compounds (asymmetrical compounds with non- zero dipole mom

Pepsi [2]

Answer:

True

Explanation:

*For polar and associated substances, methods based on four should be used four or more parameters, like analytical equation of state

*The term "analytical equation of state" implies that the function

It contains powers of v not greater than four.

*Most expressions are of the cubic type and are grouped into

the so-called cubic equations of state.

*Cubic EoS calls are very popular in simulation of

processes due to its robustness and its simple extension to mixtures.

*They are based on the van der Waals state equation of more than

100 years.

7 0

3 years ago

What observations will you look for to determine if a metal undergoes reaction?

ElenaW [278]

When a metal undergoes a reaction, especially with a nonmetal, you should look for the formation of salts or the formation of precipitates in the case the product is not soluble to water. Metals loses electrons to form positive ions which then reacts to nonmetals that are negatively charged ions.

8 0

3 years ago

Explain the need of the term avarage atomic mass

vodomira [7]

Answer:

The average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance (the decimal associated with percent of atoms of that element that are of a given isotopе). An element does not have an absolute atomic mass.

Hope this helps :)

4 0

3 years ago

A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.25 grams of aluminum foil in a solut

mrs_skeptik [129]

Answer: The correct answer is about 0.20 grams of copper (II) is formed, and some aluminum is left in the reaction mixture.

Explanation:

To calculate the number of moles, we use the formula:

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of Aluminium:

Molar mass of aluminium = 27 g/mol

Given mass of aluminium = 0.25g

Putting values in above equation, we get:

$Moles=\frac{0.25g}{27g/mol}=0.00925mol$

Moles of Copper chloride:

Molar mass of copper chloride = 134.45 g/mol

Given mass of copper chloride= 0.40g

Putting values in above equation, we get:

$Moles=\frac{0.40g}{134.45g/mol}=0.00297mol$

For the given chemical equation:

$4Al(s)+3CuCl_2(aq.)\rightarrow 2Al_2Cl_3(aq.)++3Cu(s)$

By Stoichiometry,

3 moles of Copper chloride reacts with 4 moles of aluminium

So, 0.00297 moles of copper chloride will react with = $\frac{4}{3}\times 0.00297$ = 0.00396 moles of Aluminium.

As, the required moles of aluminium is less than the given moles of aluminium. Hence, it is considered as the excess reagent.

Copper chloride is the limiting reagent in the given chemical reaction because it limits the formation of products.

By Stoichiometry of the reaction:

3 moles of copper chloride produces 3 moles of copper metal.

So, 0.00297 moles of copper chloride will produce = $\frac{3}{3}\times 0.00297$ = 0.00297 moles of copper metal.

Now, to calculate the given mass of copper metal, we use the equation required to calculate moles:

Molar mass of copper = 63.5 g/mol

Putting values in that equation, we get:

$0.00297mol=\frac{\text{given mass}}{63.5g/mol}$

Given mas of copper metal = 0.188grams (approx 0.20grams)

For the given reaction, some of the aluminum is left behind because it is the excess reagent in the reaction.

Hence, the correct answer is about 0.20 grams of copper (II) is formed, and some aluminum is left in the reaction mixture.

6 0

3 years ago

Read 2 more answers