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aivan3 [116]
3 years ago
7

Can someone solve this and show it step by step −5x + 2[x − (4 + 2x)] ≥ 5 − 2(x − 1)

Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

Step-by-step explanation:

-5x + 2(x -4 -2x) > 5 - 2x -2

-5x + 2x -8 -4x > 3 - 2x

-7x -8 > 3 - 2x

-5x > 11

x < 11:-5

x < -2.2

GREYUIT [131]3 years ago
6 0

Answer:

x ≤ 3

Step-by-step explanation:

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For what values of $j$ does the equation $(2x+7)(x-5) = -43 + jx$ have exactly one real solution? express your answer as a list
LiRa [457]

The values of 'j' are -11,5.

What is a Quadratic Equation?

  • Quadratic equations are the polynomial equations of degree 2 in one variable of the type f(x) = ax^{2} + bx + c = 0 where a, b, c, ∈ R and a ≠ 0.
  • The standard form of a quadratic equation is ax^{2} + bx + c = 0 .

Here, the given equation is (2x+7)(x-5) = - 43 + jx

On simplifying the equation we get,

2x^{2} -10x+7x-35=-43+jx\\2x^{2} -3x-35+43-jx=0\\2x^{2} -3x-jx+8=0\\2x^{2} -(3+j)x+8=0.....(1)\\

By comparing the given equation with the standard form of the quadratic equation we get,

a = 2

b = - (3 + j)

c = 8

Therefore,

(-(3+j))^{2} -4\times2\times8=0\\(3+j)^{2} -64=0\\(3+j)^{2} =64\\

Take the square root of both sides,

\sqrt{(3+j)^{2} }=\sqrt{64} \\

3 + j = ±8

Therefore,

3 + j = 8

j = 8 - 3        

j = 5

or

3 + j = -8

j = -8 - 3

j = -11

Hence, the possible values of 'j' are -11,5.

Learn more about the quadratic equation at brainly.com/question/8649555

#SPJ4

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