Answer: A. -396 kJ
Explanation:
The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.
Reversing the reaction, changes the sign of 
On multiplying the reaction by 2, enthalpy gets multiplied by 2:
Thus the enthalpy change for the reaction is -396 kJ.
Answer:
Nucleus, golgi apparatus, cell membrane
HI acts as an arrhenius acid in solution. It will dissociate into H⁺ and I⁻ therefore being a proton donor. (HI is actually one of the 7 strong acids)
I hope this helps.
Answer:
(S)−1−iodo−2−methylbutane
Explanation:
This reaction involves the substitution of iodine for bromine in (S)−1−bromo−2−methylbutane. The reaction proceeds with retention of configuration because the product is (S)−1−iodo−2−methylbutane. There is no change in the configuration of the product compound when the reaction is carried out in acetone which is a polar aprotic solvent. The reaction is shown in the image attached.
<u>Given:</u>
Volume of gas = 215 ml
Initial temperature T1 = 20C = 20 +273 = 293 K
Initial pressure P1 = 1 atm
Final pressure P2 = 1.5 atm
<u>To determine:</u>
The final temperature T2
<u>Explanation:</u>
Based on Gay-Lussac's Law:
P α T
Therefore we have the relation:
P1/T1 = P2/T2
T2 = P2T1/P1 = 1.5 *293/1 = 439.5 K
Converting from Kelvin to degrees C we have:
T2 = 439.5 - 273 = 166.5 C
Ans: The final temperature is 439.5 K or 166.5 C
